CBSE Class 10 Mathematics Basic 2023: question 22(a)
Set in the CBSE Class 10 board exam of 2023, paper 430/2/1, section B, question 22(a), for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q22(a) · 2 marks · Very short answerReal Numbers
Find the HCF of the numbers 540 and 630, using prime factorization method.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2023 board paper, set 430/2/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Break each number into a product of primes by repeated division.
Hint 2
For the HCF, take only the primes common to both numbers, each with its smaller power.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- ½ mark
- ½ mark
- 1 mark
HCF is the product of the smallest powers of the common prime factors:
Answer: HCF(540, 630) = 90
Where the marks are
- Correct prime factorisation of 540 (1/2 mark)
- Correct prime factorisation of 630 (1/2 mark)
- HCF (1 mark)
Revise the chapter
- Chapter: Real Numbers (notes, formulas, where marks are lost and every past question)
- Topic: HCF and LCM by Prime Factorisation
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.