CBSE Class 10 Mathematics Basic 2023: question 38
Set in the CBSE Class 10 board exam of 2023, paper 430/1/1, section E, question 38, for 4 marks. Try it first; the hints and our step-by-step solution are below.
Q38 · 4 marks · Case-basedCompetency-basedProbability
Blood group describes the type of blood a person has. It is a classification of blood based on the presence or absence of inherited antigenic substances on the surface of red blood cells. Blood types predict whether a serious reaction will occur in a blood transfusion.
In a sample of 50 people, 21 had type O blood, 22 had type A, 5 had type B and rest had type AB blood group.
Based on the above, answer the following questions :
- (i)1 mark
What is the probability that a person chosen at random had type O blood ?
- (ii)1 mark
What is the probability that a person chosen at random had type AB blood group ?
- (iii)2 marks
What is the probability that a person chosen at random had neither type A nor type B blood group ?
OR
(iii)2 marksWhat is the probability that person chosen at random had either type A or type B or type O blood group ?
Figure in the paper: Four cartoon blood-drop characters, each holding a yellow label: A (top left), B (top right), AB (bottom left) and O (bottom right). See it in the official paper.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2023 board paper, set 430/1/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Probability = number of favourable outcomes ÷ total number of people (50).
Hint 2
Find the AB count by subtracting the other three groups from 50.
Hint 3
'Neither A nor B' means the remaining groups, O and AB. 'A or B or O' means everyone except AB.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
(i) .
- ½ mark
(ii) Number with type AB .
- ½ mark
(ii) .
- 1 mark
(iii) A person with neither type A nor type B has type O or type AB. Favourable outcomes .
- 1 mark
(iii) .
- 1 mark
(iii) OR: Favourable outcomes for type A, B or O .
- 1 mark
(iii) OR: .
Answer: (i) 21/50; (ii) 1/25; (iii) 23/50; OR (iii) 24/25
Where the marks are
- (i) P(type O) = 21/50 (1 mark)
- (ii) Finds 2 people with type AB (½ mark)
- (ii) P(type AB) = 1/25 (½ mark)
- (iii) Favourable outcomes = 21 + 2 = 23 (1 mark)
- (iii) Probability = 23/50 (1 mark)
- (iii) OR: Favourable outcomes = 48 (1 mark)
- (iii) OR: Probability = 24/25 (1 mark)
Revise the chapter
- Chapter: Probability (notes, formulas, where marks are lost and every past question)
- Topic: Properties of Probability and Complementary Events
More questions from Probability
- 2023 board paper, set 430/2/1 (Basic), Q14 · 1 markWhich of the following numbers cannot be the probability of an event?
- 2023 board paper, set 430/2/1 (Basic), Q25 · 2 marksFrom a well-shuffled deck of 52 playing cards, all diamond cards are removed. Now, a card is drawn from the re…
- 2023 board paper, set 430/4/1 (Basic), Q6 · 1 markWhich of the following cannot be the probability of an event?
The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.