Skip to content
MathsCBSE Class 10 · Basic · Board exam 2023, set 430/1/1 · 4 marks · Case-based

CBSE Class 10 Mathematics Basic 2023: question 38

Set in the CBSE Class 10 board exam of 2023, paper 430/1/1, section E, question 38, for 4 marks. Try it first; the hints and our step-by-step solution are below.

Q38 · 4 marks · Case-basedCompetency-basedProbability

Blood group describes the type of blood a person has. It is a classification of blood based on the presence or absence of inherited antigenic substances on the surface of red blood cells. Blood types predict whether a serious reaction will occur in a blood transfusion.

In a sample of 50 people, 21 had type O blood, 22 had type A, 5 had type B and rest had type AB blood group.

Based on the above, answer the following questions :

  1. (i)

    What is the probability that a person chosen at random had type O blood ?

    1 mark
  2. (ii)

    What is the probability that a person chosen at random had type AB blood group ?

    1 mark
  3. (iii)

    What is the probability that a person chosen at random had neither type A nor type B blood group ?

    2 marks
  4. OR

    (iii)

    What is the probability that person chosen at random had either type A or type B or type O blood group ?

    2 marks

Figure in the paper: Four cartoon blood-drop characters, each holding a yellow label: A (top left), B (top right), AB (bottom left) and O (bottom right). See it in the official paper.

Source: official question paper from cbse.gov.in (PDF). See it in the full 2023 board paper, set 430/1/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

Probability = number of favourable outcomes ÷ total number of people (50).

Hint 2

Find the AB count by subtracting the other three groups from 50.

Hint 3

'Neither A nor B' means the remaining groups, O and AB. 'A or B or O' means everyone except AB.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. (i) .

    1 mark
  2. (ii) Number with type AB .

    ½ mark
  3. (ii) .

    ½ mark
  4. (iii) A person with neither type A nor type B has type O or type AB. Favourable outcomes .

    1 mark
  5. (iii) .

    1 mark
  6. (iii) OR: Favourable outcomes for type A, B or O .

    1 mark
  7. (iii) OR: .

    1 mark

Answer: (i) 21/50; (ii) 1/25; (iii) 23/50; OR (iii) 24/25

Where the marks are

  • (i) P(type O) = 21/50 (1 mark)
  • (ii) Finds 2 people with type AB (½ mark)
  • (ii) P(type AB) = 1/25 (½ mark)
  • (iii) Favourable outcomes = 21 + 2 = 23 (1 mark)
  • (iii) Probability = 23/50 (1 mark)
  • (iii) OR: Favourable outcomes = 48 (1 mark)
  • (iii) OR: Probability = 24/25 (1 mark)

Revise the chapter

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.