CBSE Class 10 Mathematics Standard 2023: question 19
Set in the CBSE Class 10 board exam of 2023, paper 30/4/1, section A, question 19, for 1 mark. Try it first; the hints and our step-by-step solution are below.
Q19 · 1 mark · Assertion-reasonCompetency-basedProbability
DIRECTIONS: In the question number 19 and 20, a statement of Assertion (A) is followed by a statement of Reason (R). Choose the correct option out of the following.
Assertion (A): The probability that a leap year has 53 Sundays is .
Reason (R): The probability that a non-leap year has 53 Sundays is .
- (A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
- (B)Both Assertion (A) and Reason (R) are true and Reason (R) is not the correct explanation of Assertion (A).
- (C)Assertion (A) is true but Reason (R) is false.
- (D)Assertion (A) is false but Reason (R) is true.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2023 board paper, set 30/4/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Write 366 and 365 as complete weeks plus some extra days.
Hint 2
Count how many of the possible extra days (or pairs of days) include a Sunday.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
A leap year has 366 days, which is 52 weeks and 2 extra days. The extra pair of days can be one of 7 equally likely pairs: (Sun, Mon), (Mon, Tue), …, (Sat, Sun). Two of these pairs contain a Sunday, so . Hence A is true.
A non-leap year has 365 days, which is 52 weeks and 1 extra day. That extra day is a Sunday in 1 case out of 7, so , not . Hence R is false.
- 1 mark
A is true but R is false. The answer is option (C).
Answer: Option (C): A true, R false
Where the marks are
- Chooses option (C) (1 mark)
Revise the chapter
- Chapter: Probability (notes, formulas, where marks are lost and every past question)
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