Mathematical Tools Used in Economics: ISC Class 11 Notes
Updated 15 October 2026 · Fact-checked
The main mathematical tool in ISC Class 11 Economics is the straight line, y = a + bx, whose slope b shows how much y changes when x rises by one unit and whose intercept a is y's value when x is zero. Linear demand, supply, cost and consumption functions are written and solved this way.
What Mathematical Tools Used in Economics is about
Economists describe relationships with functions: quantity demanded depends on price, consumption depends on income, cost depends on output. The simplest such relationship is a straight line, and its slope tells us the rate at which one variable changes with another.
The CISCE 2028 syllabus asks for: some mathematical tools used in economics: the equation of a straight line and the slope of a straight line.
This page covers the forms of a straight-line equation (slope-intercept, point-slope, two-point), how to find slope from an equation, a graph or two points, and how economists use these ideas: the slope of a demand curve, the marginal propensity to consume, marginal cost, and finding equilibrium where two lines meet. All numericals are worked in full and checked.
Weightage: Mathematical Tools Used in Economics is part of the unit Statistics of the ISC Class XI Economics syllabus. CISCE gives no Class XI unit weightage for Economics: Paper I (Theory) carries 80 marks, and the school sets the paper.Source: CISCE ISC Economics syllabus, examination year 2028, Class XI paper pattern
Key concepts
- Variables, functions and graphs
A variable is a quantity that can take different values (price, income, output).
A function shows how one variable (the dependent variable) depends on another (the independent variable): y = f(x). Examples: quantity demanded Qd = f(P); consumption C = f(Y); total cost TC = f(Q).
Graphing: plot the independent variable on the x-axis and the dependent on the y-axis (in economics, price is conventionally on the vertical axis for demand and supply curves, even though it is the independent variable).
A linear function gives a straight line on a graph: equal changes in x always cause equal changes in y.
Constants (a and b in y = a + bx) are fixed for a given relationship; they are called parameters.
Worked example
In the consumption function C = 50 + 0.8Y, identify the dependent and independent variables and the parameters. [1 mark]
Try it first, then show the solutionSolution
- Consumption depends on income: C is dependent, Y independent; 50 and 0.8 are parameters.
Answer: Dependent: C; independent: Y; parameters: 50 and 0.8.
- Equation of a straight line
Slope-intercept form: y = a + bx (also written y = mx + c), where:
- a (or c) is the intercept: the value of y when x = 0 (where the line cuts the y-axis);
- b (or m) is the slope.
Point-slope form: a line with slope b through the point (x₁, y₁): y − y₁ = b(x − x₁).
Two-point form: a line through (x₁, y₁) and (x₂, y₂): (y − y₁) ÷ (x − x₁) = (y₂ − y₁) ÷ (x₂ − x₁).
General form: Ax + By + C = 0; slope = −A ÷ B; y-intercept = −C ÷ B.
Special lines: a horizontal line y = k has slope 0; a vertical line x = k has an undefined (infinite) slope; a line through the origin has a = 0 (y = bx).
x-intercept: set y = 0 and solve for x: x = −a ÷ b.
Worked example
Find the equation of the line through (2, 7) and (6, 19). [2 marks]
Try it first, then show the solutionSolution
- Slope = (19 − 7) ÷ (6 − 2) = 12 ÷ 4 = 3.
- y − 7 = 3(x − 2) → y = 3x + 1.
Answer: y = 1 + 3x (slope 3, intercept 1).
- Slope of a straight line
The slope measures the steepness and direction of a line: the change in y per unit change in x.
Slope = Δy ÷ Δx = (y₂ − y₁) ÷ (x₂ − x₁) ('rise over run').
Sign of the slope:
- Positive: line rises from left to right (y increases with x): a supply curve, a consumption function.
- Negative: line falls from left to right (y decreases as x increases): a demand curve.
- Zero: horizontal line (y does not change): a fixed cost line.
- Infinite (undefined): vertical line (x does not change): a perfectly inelastic supply.
A straight line has a constant slope everywhere; a curve has a different slope at each point (measured by the tangent at that point).
Slope and angle: slope = tan θ, where θ is the angle the line makes with the positive x-axis. A 45° line has slope 1.
Parallel lines have equal slopes; their intercepts differ.
Worked example
Find the slope of the line 4x + 2y = 20 and its intercepts on both axes. [2 marks]
Try it first, then show the solutionSolution
- 2y = 20 − 4x → y = 10 − 2x: slope = −2, y-intercept = 10.
- x-intercept: 0 = 10 − 2x → x = 5.
Answer: Slope −2; y-intercept 10; x-intercept 5.
- Straight lines in economics: demand and supply
Linear demand function: Qd = a − bP (b > 0), so quantity demanded falls as price rises (law of demand).
- Slope of Qd with respect to P = −b (change in quantity per ₹1 rise in price).
- Drawn with P on the vertical axis, the curve's slope is ΔP ÷ ΔQ = −1 ÷ b.
- a = quantity demanded when price is zero; a ÷ b = the price at which demand falls to zero.
Linear supply function: Qs = c + dP (d > 0): supply rises with price.
Market equilibrium: Qd = Qs → a − bP = c + dP → P* = (a − c) ÷ (b + d), then Q* from either equation.
Example: Qd = 100 − 4P, Qs = 10 + 2P. Equilibrium: 100 − 4P = 10 + 2P → 6P = 90 → P* = ₹15; Q* = 100 − 60 = 40 units (check: 10 + 30 = 40).
Shifts: a change in a or c (intercept) shifts the line parallel; a change in b or d (slope) rotates it.
Worked example
Suppose Qd = 120 − 3P. Find the quantity demanded at P = ₹20, the slope of the demand function, and the price at which nothing is bought. [2 marks]
Try it first, then show the solutionSolution
- At P = 20: Qd = 120 − 60 = 60 units; slope dQ/dP = −3 (3 units fewer for each ₹1 rise).
- Qd = 0 → 3P = 120 → P = ₹40.
Answer: 60 units; slope −3; demand is zero at ₹40.
- Straight lines in economics: consumption and cost
Consumption function: C = a + bY, where a = autonomous consumption (spending even at zero income) and b = marginal propensity to consume (MPC) = ΔC ÷ ΔY, the slope. 0 < MPC < 1.
- Saving function: S = Y − C = −a + (1 − b)Y; its slope is the MPS = 1 − MPC.
- Break-even income (C = Y): Y = a ÷ (1 − b).
Linear cost function: TC = FC + vQ, where FC = fixed cost (intercept) and v = marginal cost (slope), constant for a linear function. Average cost AC = FC ÷ Q + v falls as output rises.
Revenue and break-even: if price is p, TR = pQ (a line through the origin with slope p). Break-even output where TR = TC: Q = FC ÷ (p − v).
Example: TC = 2,000 + 30Q and p = ₹55: break-even Q = 2,000 ÷ 25 = 80 units.
Worked example
Suppose C = 200 + 0.75Y. Find consumption at Y = 1,000, the MPC, the MPS, and the break-even income. [2 marks]
Try it first, then show the solutionSolution
- C = 200 + 750 = 950; MPC = 0.75 (slope); MPS = 0.25.
- Break-even: Y = 200 ÷ (1 − 0.75) = 800.
Answer: C = 950; MPC 0.75; MPS 0.25; break-even income 800.
- Slope as a rate of change; linear vs non-linear
Slope is the economist's measure of marginal change: marginal cost, marginal propensity to consume, marginal revenue all equal the slope of the relevant total curve.
Average vs marginal from a line: for TC = 2,000 + 30Q, marginal cost is always 30 (the slope), while average cost = 2,000 ÷ Q + 30 changes with Q. For a line through the origin (y = bx), average = marginal = b.
Non-linear relations: many economic curves bend (the PPC is concave; total utility rises at a falling rate). The slope then varies from point to point: between two points it is approximated by the chord, at a point by the tangent.
Example (chord slope): a PPC passes through (2, 12) and (4, 5); the average slope between them is (5 − 12) ÷ (4 − 2) = −3.5: 3.5 units of Y given up per unit of X (average MRT over the move).
Using slope to interpret graphs: a steeper demand line (larger |ΔP ÷ ΔQ|) means quantity responds less to price over that range; a flatter consumption line means a smaller MPC.
Worked example
Suppose TC = 2,000 + 30Q. Find MC and AC at Q = 50 and Q = 100. [2 marks]
Try it first, then show the solutionSolution
- MC = slope = ₹30 at every output.
- AC(50) = 2,000 ÷ 50 + 30 = ₹70; AC(100) = 20 + 30 = ₹50.
Answer: MC = ₹30 throughout; AC = ₹70 at 50 units and ₹50 at 100 units.
Mathematical Tools Used in Economics in real life
Each concept, met in an everyday situation. Read the situation, answer the question in your own words, then compare with the model answer. The one-line hook is what to remember.
Slope of a phone plan
Suppose a mobile plan charges a fixed ₹199 a month plus ₹2 for every GB of data beyond the free limit.
Write the monthly bill as a straight line, and find the bill for 15 extra GB.
Try it first, then show the solutionSolution
- Bill B = 199 + 2G, where G = extra GB: intercept 199 (fixed charge), slope 2 (₹ per extra GB).
- For G = 15: B = 199 + 30 = ₹229.
Answer: B = 199 + 2G; ₹229 for 15 extra GB.
Memory hook: Intercept = what you pay anyway; slope = the price of one more.
Break-even for a stall
Imagine you run a lemonade stall at a school fair: the stall fee is ₹600, each cup costs ₹8 to make, and you sell at ₹20.
How many cups must you sell to break even?
Try it first, then show the solutionSolution
- TC = 600 + 8Q; TR = 20Q.
- TR = TC → 12Q = 600 → Q = 50 cups.
Answer: 50 cups; every cup after that adds ₹12 profit.
Memory hook: Break-even = fixed cost ÷ (price − cost per unit).
MPC at home
Suppose your family's monthly spending rises from ₹40,000 to ₹46,000 when its income rises from ₹50,000 to ₹58,000.
What is the family's MPC, and what does it mean?
Try it first, then show the solutionSolution
- MPC = ΔC ÷ ΔY = 6,000 ÷ 8,000 = 0.75.
- Of every extra ₹100 earned, the family spends ₹75 and saves ₹25.
Answer: MPC = 0.75: three-quarters of extra income is spent.
Memory hook: MPC is the slope of the spending line.
Topics in this chapter
Mathematical Tools Used in Economics: key facts
- Slope-intercept form
- y = a + bx
- a = intercept, b = slope.
- Slope from two points
- b = (y₂ − y₁) ÷ (x₂ − x₁)
- Point-slope form
- y − y₁ = b(x − x₁)
- Slope of the general form
- For Ax + By + C = 0: slope = −A ÷ B; y-intercept = −C ÷ B
- Linear equilibrium
- Qd = a − bP, Qs = c + dP ⇒ P* = (a − c) ÷ (b + d)
- Break-even
- Q = FC ÷ (p − v); break-even income Y = a ÷ (1 − MPC)
Mathematical Tools Used in Economics: diagrams to practise
Practise each one on paper: draw it from the checklist, then tick off every label.
Slope and intercept of a line
Explain the equation and slope of a straight line.
Draw
- Axes x and y; draw a rising line cutting the y-axis at a.
- Pick two points; draw a right-angled triangle below the line showing Δx (horizontal side) and Δy (vertical side).
- Label slope = Δy ÷ Δx and the intercept a; mark the angle θ with the x-axis (slope = tan θ).
Label
- intercept a
- Δx
- Δy
- θ
- slope b
Watch out: Draw a second, falling line to show a negative slope for contrast.
Linear demand and supply equilibrium
Find equilibrium from linear equations and show it on a graph.
Draw
- Price on the vertical axis, quantity on the horizontal (economists' convention).
- Demand Qd = 100 − 4P: plot (100, 0) and (0, 25) and join. Supply Qs = 10 + 2P: plot (10, 0) and (50, 20) and join.
- Mark the intersection E (40, 15); draw dotted lines to both axes.
Label
- D
- S
- E
- P* = 15
- Q* = 40
Watch out: Calculate two points of each line before drawing; check the intersection against your algebra.
How the school exam asks Mathematical Tools Used in Economics
The question patterns to expect, and the method that works for each.
| Question type | How it is asked | Method |
|---|---|---|
| Equation and slope (1-4 marks) | Find the slope and intercepts of a line; equation through two points or with a given slope; interpret the sign of the slope. | Rearrange to y = a + bx; use the two-point or point-slope form; state meaning. |
| Economic applications (2-6 marks) | Linear demand and supply: equilibrium; consumption function: MPC, MPS, break-even income; cost function: MC, AC, break-even output. | Write the function; identify slope and intercept with economic meaning; solve; verify. |
| Graphs (2-4 marks) | Plot linear functions and read the intersection; compare slopes of two lines. | Two points per line, labelled axes with units, mark intercepts and intersection. |
Tricks to remember Mathematical Tools Used in Economics
Short memory aids. Say each one aloud once, then use it on a question the same day.
Rise over run
Slope = how far up (or down) ÷ how far across.
Use it when: Computing slope from two points.
Intercept is the 'anyway' amount
Fixed cost, autonomous consumption, fixed charge: what happens when x = 0.
Use it when: Interpreting a.
Slope is the 'one more' amount
Marginal cost, MPC, price per unit: change in y for one more x.
Use it when: Interpreting b.
Equilibrium: set equal, solve, substitute, check
Qd = Qs → P* → Q* from both equations.
Use it when: Linear market models.
Mathematical Tools Used in Economics: exam-level solved questions
Ordered from exam level to HOTS. Cover the solution, write your own, then compare step by step.
Example 1: Sign of slope · 1 mark · MCQExam level
The slope of a linear demand function Qd = 80 − 5P is:
(a) 80
(b) 5
(c) −5
(d) 16
Try it first, then show the solutionSolution
- In y = a + bx form, b = −5.
Answer: (c) −5.
Example 2: Parallel lines · 1 mark · Assertion-reasonHarder exam level
Assertion: The lines C = 100 + 0.8Y and C = 150 + 0.8Y are parallel.
Reason: Lines with the same slope are parallel.
(a) Both Assertion and Reason are true and Reason is the correct explanation of Assertion.
(b) Both Assertion and Reason are true but Reason is not the correct explanation of Assertion.
(c) Assertion is true but Reason is false.
(d) Both Assertion and Reason are false.
Try it first, then show the solutionSolution
- Both have slope (MPC) 0.8; only the intercepts differ: the Reason explains the Assertion.
Answer: (a)
Example 3: Equation from two points · 2 marks · Short answerExam level
Suppose at a price of ₹10 consumers buy 60 units and at ₹16 they buy 42 units. Assuming a linear demand function Qd = a − bP, find a and b.
Try it first, then show the solutionSolution
- b = −(42 − 60) ÷ (16 − 10) = 18 ÷ 6 = 3, so Qd falls 3 units per ₹1.
- 60 = a − 3 × 10 → a = 90. Qd = 90 − 3P.
Answer: Qd = 90 − 3P (a = 90, b = 3).
Example 4: Equilibrium and a shift · 4 marks · Short answerHarder exam level
Suppose Qd = 100 − 4P and Qs = 10 + 2P. (a) Find the equilibrium price and quantity. (b) If income rises and demand becomes Qd = 130 − 4P, find the new equilibrium. (c) What kind of change in the demand line is this?
Try it first, then show the solutionSolution
- (a) 100 − 4P = 10 + 2P → 6P = 90 → P* = 15; Q* = 100 − 60 = 40.
- (b) 130 − 4P = 10 + 2P → 6P = 120 → P* = 20; Q* = 130 − 80 = 50 (check: 10 + 40 = 50).
- (c) The intercept rose from 100 to 130 with the same slope: a parallel rightward shift of demand.
Answer: (a) ₹15, 40 units; (b) ₹20, 50 units; (c) a parallel shift (intercept change, same slope).
Example 5: Consumption and saving functions · 4 marks · Short answerHarder exam level
Suppose consumption is ₹300 crore when income is zero and rises by ₹80 crore for every ₹100 crore rise in income. (a) Write the consumption function. (b) Write the saving function. (c) Find the break-even income. (d) Find saving at an income of ₹2,000 crore.
Try it first, then show the solutionSolution
- (a) MPC = 80 ÷ 100 = 0.8: C = 300 + 0.8Y.
- (b) S = Y − C = −300 + 0.2Y.
- (c) S = 0 → 0.2Y = 300 → Y = ₹1,500 crore.
- (d) S = −300 + 0.2 × 2,000 = ₹100 crore.
Answer: (a) C = 300 + 0.8Y; (b) S = −300 + 0.2Y; (c) ₹1,500 crore; (d) ₹100 crore.
Example 6: Break-even and profit line · 6 marks · Long answerHOTS / competency
Suppose a firm's fixed cost is ₹12,000, variable cost ₹40 per unit, and it sells at ₹70 per unit. (a) Write the TC and TR equations and their slopes. (b) Find the break-even output. (c) Write the profit function and its slope. (d) Find the output needed for a profit of ₹9,000. (e) If the price falls to ₹64, what is the new break-even output?
Try it first, then show the solutionSolution
- (a) TC = 12,000 + 40Q (slope 40 = MC); TR = 70Q (slope 70 = price).
- (b) 70Q = 12,000 + 40Q → 30Q = 12,000 → Q = 400 units.
- (c) Profit π = TR − TC = −12,000 + 30Q; slope 30 (profit per extra unit beyond break-even).
- (d) 9,000 = −12,000 + 30Q → Q = 700 units.
- (e) 24Q = 12,000 → Q = 500 units.
Answer: (a) TC = 12,000 + 40Q, TR = 70Q; (b) 400 units; (c) π = −12,000 + 30Q, slope 30; (d) 700 units; (e) 500 units.
Example 7: Slope along a curve · 2 marks · Short answerHOTS / competency
Suppose a PPC passes through (0, 15), (2, 12) and (4, 5) (X, Y). Find the slope of the chord between the first two points and between the last two, and explain what the change shows.
Try it first, then show the solutionSolution
- (0, 15) to (2, 12): slope = (12 − 15) ÷ 2 = −1.5.
- (2, 12) to (4, 5): slope = (5 − 12) ÷ 2 = −3.5. The slope becomes steeper: the opportunity cost of X (MRT) is rising, so the PPC is concave.
Answer: −1.5 and −3.5; the steeper slope shows increasing marginal opportunity cost (a concave PPC).
Case-study practice (Section C style)
Read the situation, then answer every part. In a school exam set on the board pattern this is a 4-mark question split into 1 + 2 + 1 marks.
The cycle-repair shop
Suppose Rahul's cycle-repair shop has monthly fixed costs (rent and tools) of ₹9,000. Each repair uses parts and his time worth ₹60 and he charges ₹150 per repair. Last month he did 80 repairs.
(i) · 1 mark
Write the TC and TR equations.
Answer
Answer: TC = 9,000 + 60Q; TR = 150Q.
½ mark each.
(ii) · 2 marks
Find his break-even number of repairs and last month's profit.
Answer
Answer: Break-even: 90Q = 9,000 → Q = 100 repairs. Last month: TR = 12,000, TC = 9,000 + 4,800 = 13,800, loss = ₹1,800.
1 mark each.
(iii) · 1 mark
If he raises his charge to ₹180, how many repairs does he need to break even?
Answer
Answer: 120Q = 9,000 → Q = 75 repairs.
1 mark.
Where the marks are
How a typical answer is split into step marks. Show every step: a right final answer alone rarely earns full marks.
Linear demand from two points (2 marks) (2 marks)
| Step | Marks |
|---|---|
| Slope b correctly found | 1 |
| Intercept a and the equation | 1 |
Equilibrium and shift (4 marks) (4 marks)
| Step | Marks |
|---|---|
| Original P* and Q* | 1 |
| New P* and Q* with check | 2 |
| Type of shift explained | 1 |
Break-even and profit line (6 marks) (6 marks)
| Step | Marks |
|---|---|
| TC and TR with slopes | 1 |
| Break-even output | 1 |
| Profit function and slope | 1 |
| Output for target profit | 2 |
| New break-even after price change | 1 |
Where students lose marks in Mathematical Tools Used in Economics
The slips examiners see most often, and what to write instead.
Mistake: Reading the slope from the wrong variable
In Qd = a − bP, b is ΔQ ÷ ΔP; on a graph with P vertical, the visual slope is ΔP ÷ ΔQ = −1 ÷ b.
Do this: State which variable is on which axis before giving the slope.
Usually costs: 1 mark.
Mistake: Dropping the minus sign of a demand slope
The negative sign carries the economic meaning (law of demand).
Do this: Keep signs; interpret them.
Usually costs: 1 mark.
Mistake: Not rearranging Ax + By + C = 0 before reading the slope
The coefficient of x is not the slope unless y stands alone.
Do this: Solve for y first, or use slope = −A ÷ B.
Usually costs: 1 mark.
Mistake: Not checking equilibrium in both equations
An arithmetic slip goes unnoticed; Qd and Qs must be equal at P*.
Do this: Substitute P* into both equations.
Usually costs: 1 mark.
Practice questions on Mathematical Tools Used in Economics
Write each answer on paper first. Open the hint only if you are stuck, and the answer only when you have finished.
Q1 · 1 mark · MCQExam level
A horizontal straight line has a slope of:
(a) 1
(b) 0
(c) −1
(d) infinityHint
No change in y.
Answer
(b) 0.
Q2 · 1 mark · Very short answerExam level
Find the slope of the line through (3, 8) and (7, 20).
Hint
Δy ÷ Δx.
Answer
(20 − 8) ÷ (7 − 3) = 12 ÷ 4 = 3.
Q3 · 2 marks · Short answerExam level
Write the equation of a line with slope −2 passing through (4, 10), and find its y-intercept.
Hint
Point-slope form.
Answer
y − 10 = −2(x − 4) → y = 18 − 2x; y-intercept 18.
Q4 · 2 marks · Short answerHarder exam level
Suppose Qd = 200 − 5P and Qs = −40 + 7P. Find the equilibrium price and quantity.
Hint
Set equal.
Answer
200 − 5P = −40 + 7P → 12P = 240 → P* = ₹20; Q* = 200 − 100 = 100 units (check: −40 + 140 = 100).
Q5 · 2 marks · Short answerHarder exam level
Find the slope and both intercepts of 3x + 5y − 30 = 0.
Hint
Solve for y.
Answer
y = 6 − 0.6x: slope −0.6; y-intercept 6; x-intercept 10.
Q6 · 4 marks · Short answerHarder exam level
Suppose C = 120 + 0.6Y. Find the MPS, the saving function and the break-even income. At Y = 500, is there saving or dissaving?
Hint
S = Y − C.
Answer
MPS = 1 − 0.6 = 0.4; S = −120 + 0.4Y; break-even Y = 120 ÷ 0.4 = 300. At Y = 500, S = −120 + 200 = 80: positive saving.
Q7 · 4 marks · Short answerHOTS / competency
Suppose a taxi charges ₹50 plus ₹14 per km, and an app cab charges ₹20 plus ₹16 per km. For what distance do they cost the same? Which is cheaper for a 25 km trip?
Hint
Two lines; find their intersection.
Answer
50 + 14d = 20 + 16d → d = 15 km (cost ₹260 each). For 25 km: taxi 50 + 350 = ₹400; app cab 20 + 400 = ₹420. The taxi is cheaper beyond 15 km because its slope (₹14) is lower.
Q8 · 2 marks · Short answerHOTS / competency
Suppose two consumption functions are C₁ = 100 + 0.9Y and C₂ = 300 + 0.7Y. At what income do they give equal consumption, and which household spends more at higher incomes?
Hint
Slopes decide who overtakes.
Answer
100 + 0.9Y = 300 + 0.7Y → Y = 1,000 (C = 1,000 for both). Above Y = 1,000 the first household spends more, because its MPC (slope 0.9) is higher.
Q9 · 4 marks · Short answerHarder exam level
Explain the importance of the slope of a straight line in economics with three examples.
Hint
Marginal concepts.
Answer
Slope shows the rate of change of one variable with another, i.e. the marginal value. In a consumption function, the slope is the MPC (how much of extra income is spent). In a total cost function, the slope is the marginal cost (cost of one more unit). In a demand function, the slope shows how much quantity demanded changes per ₹1 change in price (negative, by the law of demand). Slopes also tell whether lines are parallel (same slope) and where they intersect.
Q10 · 6 marks · Long answerHOTS / competency
Suppose market demand is Qd = 90 − 3P and supply Qs = 10 + 5P. The government fixes a maximum price of ₹7. (a) Find the equilibrium. (b) Find the shortage at ₹7. (c) Show that the shortage equals (b + d) × (P* − ceiling).
Hint
Use the linear forms.
Answer
(a) 90 − 3P = 10 + 5P → 8P = 80 → P* = ₹10; Q* = 60. (b) At ₹7: Qd = 69, Qs = 45, shortage = 24 units. (c) (b + d)(P* − 7) = (3 + 5)(10 − 7) = 8 × 3 = 24: equal, because below P* demand rises by 3 and supply falls by 5 for each ₹1 cut in price.
Test your recall
Answer in your head or on paper first, then open the card. Pulling an answer out of memory makes it stick far better than re-reading.
1.Slope-intercept form?Show answer
y = a + bx.
2.Slope from two points?Show answer
(y₂ − y₁) ÷ (x₂ − x₁).
3.Slope of a vertical line?Show answer
Undefined (infinite).
4.Slope of C = a + bY?Show answer
b, the MPC.
5.Equilibrium price for Qd = a − bP, Qs = c + dP?Show answer
(a − c) ÷ (b + d).
6.Break-even output?Show answer
FC ÷ (p − v).
Best order to study it
- Variables, functions and graphs.
- Forms of a straight-line equation.
- Slope: meaning, sign, from two points and equations.
- Linear demand, supply and equilibrium.
- Consumption, saving and cost functions; break-even.
- Slope as marginal change; chords on curves.
Quick revision checklist
The night before the exam: can you do each of these without looking?
- y = a + bx: a intercept, b slope.
- Slope = Δy ÷ Δx; positive rises, negative falls, zero flat, infinite vertical.
- Point-slope: y − y₁ = b(x − x₁); general form slope = −A ÷ B.
- Qd = a − bP; Qs = c + dP; P* = (a − c) ÷ (b + d).
- C = a + bY: b = MPC; S = −a + (1 − b)Y; break-even Y = a ÷ (1 − b).
- TC = FC + vQ: MC = v; break-even Q = FC ÷ (p − v).
Mathematical Tools Used in Economics: frequently asked questions
Why do economists put price on the vertical axis?
It is a convention dating back to Alfred Marshall. Mathematically, price is the independent variable in a demand function, but demand and supply diagrams show it on the vertical axis, so the visual slope of a demand curve is ΔP ÷ ΔQ.
Is the slope of a demand curve the same as its elasticity?
No. Slope is the absolute change (units per rupee); elasticity is the ratio of percentage changes. Along a straight-line demand curve the slope is constant but elasticity changes from point to point.
How much mathematics does this chapter require?
Only the equation and slope of a straight line, as the syllabus says: finding slopes and intercepts, forming equations, solving two linear equations, and interpreting the results in economic terms.
Based on: CISCE ISC 2028 Economics syllabus (Classes XI and XII); CISCE Regulations for the ISC Examination Year 2028 (Class XI internal examination)