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EconomicsISC Class 11 · Chapter 15

Correlation: ISC Class 11 Economics Notes and Numericals

Updated 15 October 2026 · Fact-checked

Correlation measures the direction and strength of the relationship between two variables, such as price and quantity demanded. ISC Class 11 Economics covers the types and degrees of correlation, the scatter diagram, Karl Pearson's coefficient for two variables with ungrouped data, and Spearman's rank correlation, including tied ranks, with numericals.

What Correlation is about

Economics is full of pairs of variables that move together: income and consumption, price and demand, rainfall and crop output, advertising and sales. Correlation tells us whether such pairs move in the same or opposite direction, and how closely.

The CISCE 2028 syllabus asks for: correlation: introduction, its meaning and significance, types and degrees; the scatter diagram; Karl Pearson's coefficient of correlation (two variables, ungrouped data); and Spearman's coefficient of rank correlation, with numericals.

Remember throughout: correlation measures association, not causation. A high r between two variables does not prove that one causes the other. Every numerical below shows the full working table, which is where the step marks are.

Weightage: Correlation is part of the unit Statistics of the ISC Class XI Economics syllabus. CISCE gives no Class XI unit weightage for Economics: Paper I (Theory) carries 80 marks, and the school sets the paper.Source: CISCE ISC Economics syllabus, examination year 2028, Class XI paper pattern

Key concepts

Meaning and significance of correlation

Correlation is a statistical measure of the degree and direction of the linear relationship between two variables: when one changes, does the other tend to change, and by how much?

The coefficient of correlation (r) lies between −1 and +1.

Significance (uses) in economics:

1. Tests economic relationships: price and quantity demanded (expected negative), income and consumption (positive).
2. Helps prediction: if two variables are highly correlated, one helps estimate the other (the basis of regression).
3. Helps policy: knowing that credit and investment are positively related guides monetary policy.
4. Helps business decisions: advertising and sales, price and sales.

Correlation and causation: correlation shows that variables move together; it does not prove that one causes the other. Two variables can be correlated because a third factor drives both (ice-cream sales and drowning cases both rise in summer), or by pure chance (spurious or nonsense correlation).

Worked example

Suppose a study finds a high positive correlation between the number of umbrellas sold and the number of people with colds in a city. Does buying umbrellas cause colds? [1 mark]

Try it first, then show the solutionSolution
  1. Both rise in the rainy season: a third factor (rain or season) affects both.

Answer: No. The correlation is due to a common cause (the rainy season), not causation.

Types and degrees of correlation

Types:

1. Positive (direct): both variables move in the same direction (income and consumption; price and supply).
2. Negative (inverse): they move in opposite directions (price and quantity demanded; interest rate and investment).
3. Linear: the ratio of change is constant; points lie near a straight line.
4. Non-linear (curvilinear): the ratio of change varies; points follow a curve.
5. Simple: two variables; partial and multiple: more than two (beyond this syllabus).

Degrees (a common rule of thumb):

Value of rDegree
+1 or −1Perfect correlation
0.75 to 1 (or −0.75 to −1)High degree
0.50 to 0.75Moderate degree
0.25 to 0.50Low degree
Below 0.25Very low degree
0No (linear) correlation

An r of 0 means no linear relationship; a non-linear relationship may still exist.

Worked example

Classify: (i) r = −0.92 between price and demand; (ii) r = 0.40 between study hours and marks. [1 mark]

Try it first, then show the solutionSolution
  1. (i) Negative and above 0.75 in size: high negative correlation.
  2. (ii) Positive between 0.25 and 0.5: low positive correlation.

Answer: (i) High negative; (ii) low positive.

Scatter diagram

A scatter diagram plots each pair of values (X, Y) as a dot. The pattern of dots shows the direction and approximate strength of correlation.

Pattern of dotsCorrelation
On a rising straight linePerfect positive (r = +1)
Closely around a rising lineHigh positive
Widely around a rising lineLow positive
On a falling straight linePerfect negative (r = −1)
Closely around a falling lineHigh negative
No pattern, scatteredNo correlation (r ≈ 0)
Along a curveNon-linear

Merits: simple and visual; shows direction, outliers and non-linearity at a glance; not affected by extreme values the way r is.

Demerits: gives no exact numerical value; judgement of 'closeness' is subjective.

Worked example

Suppose plotting rainfall against wheat yield gives dots that rise at first and then fall at very high rainfall. What does this show? [1 mark]

Try it first, then show the solutionSolution
  1. The dots follow a curve, not a straight line.

Answer: A non-linear (curvilinear) relationship: yield rises with rain up to a point, then falls with excess rain.

Karl Pearson's coefficient of correlation

Karl Pearson's coefficient (the product moment coefficient) for two variables with ungrouped data:

Actual mean method: , where and .

Assumed mean (short-cut) method:

Example: income (X, ₹ thousand) and consumption (Y, ₹ thousand) of 5 households:

XYxyx²y²xy
2018−10−71004970
2521−5−4251620
302601010
35285325915
40321071004970

Means: 30 and 25. Σx² = 250, Σy² = 124, Σxy = 175.

r = 175 ÷ √(250 × 124) = 175 ÷ √31,000 = 175 ÷ 176.07 = +0.99: very high positive correlation, as theory predicts.

Properties: (1) −1 ≤ r ≤ +1; (2) independent of change of origin and scale (subtracting or dividing by constants does not change r, which is why the short-cut methods work); (3) r is the same whether X is correlated with Y or Y with X; (4) r = 0 means no linear relationship.

Merits: gives both direction and degree as a precise number. Demerits: assumes a linear relationship; affected by extreme values; tedious; can be misread as causation.

Worked example

Suppose that for the rate of interest (X) and private investment (Y) over several years, Σxy = −96, Σx² = 40 and Σy² = 360 (deviations from the means). Find r and interpret it. [2 marks]

Try it first, then show the solutionSolution
  1. r = −96 ÷ √(40 × 360) = −96 ÷ √14,400 = −96 ÷ 120 = −0.80.
  2. High negative correlation (above 0.75 in size): years of higher interest rates go with lower investment, as theory predicts.

Answer: r = −0.80: high negative correlation between the interest rate and investment.

Spearman's rank correlation

When variables are qualitative (beauty, honesty, taste) or only ranks are available, or when there are extreme values, use Spearman's rank correlation coefficient:

where D = difference between the two ranks of each item and N = number of pairs.

Steps: (1) rank each variable (highest = 1, or lowest = 1, but the same rule for both); (2) find D = R1 − R2 (check that ΣD = 0); (3) square and add; (4) apply the formula.

Example (no ties): two judges rank 10 dancers:

DancerABCDEFGHIJ
Judge 112345678910
Judge 231426597108
D²4114114114

ΣD² = 22; = 1 − (6 × 22) ÷ (1,000 − 10) = 1 − 132 ÷ 990 = 0.87: high agreement between the judges.

Tied ranks: give each tied item the average of the ranks they would occupy (two items tied for 2nd and 3rd both get 2.5). Then add a correction factor for each tie group:

where m = number of items sharing a rank in a group.

Merits: simple; suits qualitative data; not affected by extreme values. Demerits: uses ranks, so information in the actual values is lost; tedious for large N.

Worked example

Suppose for 7 pairs of ranks ΣD² = 14. Find Spearman's rank correlation. [1 mark]

Try it first, then show the solutionSolution
  1. r_s = 1 − (6 × 14) ÷ (343 − 7) = 1 − 84 ÷ 336 = 1 − 0.25 = 0.75.

Answer: 0.75 (high positive).

Choosing between Pearson and Spearman
BasisKarl Pearson's rSpearman's r_s
DataQuantitative valuesRanks or qualitative data
UsesActual valuesOnly the order
Extreme valuesAffectedNot much affected
AssumptionLinear relationshipMonotonic relationship (consistently rising or falling)
CalculationLongerSimpler

For the same data the two can differ, because ranking discards the size of differences between values.

Interpreting r: always state direction (positive or negative), degree (high, moderate, low) and the economic meaning (for example, 'consumption rises with income'). Add a caution that correlation is not causation where relevant.

Worked example

Which coefficient would you use to measure the agreement between two food critics who rank 8 restaurants? Why? [1 mark]

Try it first, then show the solutionSolution
  1. The data are ranks of a qualitative attribute (taste).

Answer: Spearman's rank correlation, because only ranks of a qualitative characteristic are available.

Correlation in real life

Each concept, met in an everyday situation. Read the situation, answer the question in your own words, then compare with the model answer. The one-line hook is what to remember.

Correlation is not causation

Suppose a survey of students finds that those with bigger shoe sizes score higher in reading tests.

Do big feet make better readers?

Try it first, then show the solutionSolution
  1. The survey includes students of different ages; older students have bigger feet and also read better.
  2. Age is the third factor driving both, so the correlation is not causal.

Answer: No. Age drives both shoe size and reading ability; the correlation reflects a common cause.

Memory hook: Look for the hidden third variable.

Rank correlation in daily life

Imagine you and a friend each rank five films from best (1) to worst (5). Your ranks are 1, 2, 3, 4, 5; your friend's are 2, 1, 4, 3, 5.

How closely do your tastes agree?

Try it first, then show the solutionSolution
  1. D = −1, 1, −1, 1, 0; ΣD² = 4.
  2. r_s = 1 − (6 × 4) ÷ (125 − 5) = 1 − 24 ÷ 120 = 0.8.

Answer: r_s = 0.8: high agreement in taste.

Memory hook: Rank, subtract, square, sum, plug in.

Negative correlation

Suppose you notice that on days the canteen raises samosa prices, it sells fewer samosas.

What type of correlation would you expect between price and sales, and what economic law does it reflect?

Try it first, then show the solutionSolution
  1. Higher price, lower sales: the variables move in opposite directions.
  2. This reflects the law of demand.

Answer: Negative correlation, reflecting the law of demand.

Memory hook: Opposite directions → minus sign.

Topics in this chapter

Correlation: key facts

Karl Pearson (actual mean)
x and y are deviations from the respective means.
Karl Pearson (assumed mean)
Spearman's rank correlation
Spearman with tied ranks
One correction term for each group of tied ranks.

Correlation: diagrams to practise

Practise each one on paper: draw it from the checklist, then tick off every label.

Scatter diagrams for different degrees

Explain the scatter diagram method; show types of correlation.

Draw

  1. Six small panels with X on the horizontal axis and Y on the vertical axis.
  2. (1) dots exactly on a rising line: r = +1; (2) dots close to a rising line: high positive; (3) dots on a falling line: r = −1; (4) dots close to a falling line: high negative; (5) dots scattered with no pattern: r = 0; (6) dots along a curve: non-linear.
  3. Title each panel.

Label

  • perfect positive
  • high positive
  • perfect negative
  • high negative
  • no correlation
  • non-linear

Watch out: Draw axes and label variables in every panel; an unlabelled sketch shows nothing.

Scatter diagram from data

Draw a scatter diagram for given data and comment.

Draw

  1. Choose scales so that the points fill the graph; state the scale.
  2. Plot each (X, Y) pair as a dot (no joining lines).
  3. Comment on direction and closeness; optionally draw a freehand line of best fit.

Label

  • X variable with unit
  • Y variable with unit
  • scale

Watch out: Never join the dots; a scatter diagram is not a line graph.

How the school exam asks Correlation

The question patterns to expect, and the method that works for each.

Question typeHow it is askedMethod
Concepts (1-4 marks)Meaning and significance; types and degrees; scatter diagram; correlation vs causation; properties of r.Definition, examples from economics, small sketches of scatter diagrams.
Karl Pearson numerical (4-6 marks)Calculate r for two series (ungrouped), by actual or assumed mean method; interpret.Seven-column table (X, Y, x, y, x², y², xy); formula; substitution; interpretation.
Spearman numerical (2-6 marks)Rank correlation from ranks, from marks (convert to ranks), or with ties; find a missing rank or D².Rank columns; D; D²; correction for ties; formula; interpretation.

Tricks to remember Correlation

Short memory aids. Say each one aloud once, then use it on a question the same day.

  • Same direction, plus; opposite, minus

    The sign of r tells the direction; the size tells the strength.

    Use it when: Interpreting r.

  • Spearman: 1 − 6ΣD² over N cubed minus N

    'One minus six D-squared, over n-cubed minus n.'

    Use it when: Spearman's formula.

  • Ties share the average rank

    Two tied for 3rd and 4th → 3.5 each; add (m³ − m)/12 for each tie.

    Use it when: Tied ranks.

  • Correlation ≠ causation

    Ice-cream and drowning both rise in summer.

    Use it when: Limits of correlation.

Correlation: exam-level solved questions

Ordered from exam level to HOTS. Cover the solution, write your own, then compare step by step.

Example 1: Range of r · 1 mark · MCQExam level

The value of Karl Pearson's coefficient of correlation lies between:
(a) 0 and 1
(b) −1 and 0
(c) −1 and +1
(d) −∞ and +∞

Try it first, then show the solutionSolution
  1. r is bounded by −1 and +1.

Answer: (c) −1 and +1.

Example 2: Change of scale · 1 mark · Assertion-reasonHarder exam level

Assertion: If all values of X are converted from rupees to thousands of rupees, the correlation between X and Y does not change.
Reason: The coefficient of correlation is independent of change of origin and scale.
(a) Both Assertion and Reason are true and Reason is the correct explanation of Assertion.
(b) Both Assertion and Reason are true but Reason is not the correct explanation of Assertion.
(c) Assertion is true but Reason is false.
(d) Both Assertion and Reason are false.

Try it first, then show the solutionSolution
  1. Dividing by 1,000 is a change of scale, which leaves r unchanged: the Reason explains the Assertion.

Answer: (a)

Example 3: Spearman from marks with ties · 2 marks · Short answerExam level

Suppose two subjects' marks of 7 students are: Economics 80, 72, 72, 65, 60, 55, 50; Accounts 70, 75, 68, 60, 62, 50, 48. Calculate the rank correlation.

Try it first, then show the solutionSolution
  1. Ranks (highest = 1): Eco 1, 2.5, 2.5, 4, 5, 6, 7; Acc 2, 1, 3, 5, 4, 6, 7.
  2. D = −1, 1.5, −0.5, −1, 1, 0, 0; ΣD² = 1 + 2.25 + 0.25 + 1 + 1 = 5.5. One tie of 2: correction = (8 − 2) ÷ 12 = 0.5.
  3. r_s = 1 − 6(5.5 + 0.5) ÷ (343 − 7) = 1 − 36 ÷ 336 = 0.89.

Answer: r_s ≈ 0.89: high positive correlation.

Example 4: Pearson's r: advertising and sales · 4 marks · Short answerHarder exam level

Suppose a firm's advertising (X, ₹ lakh) and sales (Y, ₹ lakh) over 7 months were: X 2, 4, 6, 8, 10, 12, 14; Y 30, 34, 33, 40, 45, 44, 54. Calculate Karl Pearson's r.

Try it first, then show the solutionSolution
  1. Means: X̄ = 56 ÷ 7 = 8; Ȳ = 280 ÷ 7 = 40.
  2. x = −6, −4, −2, 0, 2, 4, 6; y = −10, −6, −7, 0, 5, 4, 14.
  3. Σx² = 112; Σy² = 100 + 36 + 49 + 0 + 25 + 16 + 196 = 422; Σxy = 60 + 24 + 14 + 0 + 10 + 16 + 84 = 208.
  4. r = 208 ÷ √(112 × 422) = 208 ÷ √47,264 = 208 ÷ 217.40 = 0.96.

Answer: r ≈ +0.96: high positive correlation between advertising and sales.

Example 5: Rank correlation with two kinds of ties · 6 marks · Long answerHOTS / competency

Suppose the marks of 10 students in Statistics (X) and Economics (Y) are: X 48, 33, 40, 9, 16, 16, 65, 24, 16, 57; Y 13, 13, 24, 6, 15, 4, 20, 9, 6, 19. Calculate Spearman's rank correlation (highest mark = rank 1).

Try it first, then show the solutionSolution
  1. X ranks: 65 → 1, 57 → 2, 48 → 3, 40 → 4, 33 → 5, 24 → 6, the three 16s share ranks 7, 8, 9 → 8 each, 9 → 10. So: 3, 5, 4, 10, 8, 8, 1, 6, 8, 2.
  2. Y ranks: 24 → 1, 20 → 2, 19 → 3, 15 → 4, the two 13s share 5, 6 → 5.5 each, 9 → 7, the two 6s share 8, 9 → 8.5 each, 4 → 10. So: 5.5, 5.5, 1, 8.5, 4, 10, 2, 7, 8.5, 3.
  3. D = −2.5, −0.5, 3, 1.5, 4, −2, −1, −1, −0.5, −1; D² = 6.25, 0.25, 9, 2.25, 16, 4, 1, 1, 0.25, 1; ΣD² = 41.
  4. Corrections: X has one tie of 3: (27 − 3) ÷ 12 = 2; Y has two ties of 2: 0.5 + 0.5 = 1. Total = 3.
  5. r_s = 1 − 6(41 + 3) ÷ (1,000 − 10) = 1 − 264 ÷ 990 = 1 − 0.267 = 0.73.
  6. Moderate-to-high positive correlation: students who do well in Statistics tend to do well in Economics.

Answer: r_s ≈ 0.73 (moderate to high positive correlation).

Example 6: Price and demand · 4 marks · Short answerHOTS / competency

Suppose the price (X, ₹) and quantity demanded (Y, units) of a good were: X 10, 12, 14, 16, 18, 20; Y 40, 38, 32, 30, 26, 20. (a) Calculate r. (b) Does the result support the law of demand? (c) Would r change if prices were measured in paise?

Try it first, then show the solutionSolution
  1. (a) X̄ = 15, Ȳ = 31; x = −5, −3, −1, 1, 3, 5; y = 9, 7, 1, −1, −5, −11.
  2. Σx² = 70; Σy² = 81 + 49 + 1 + 1 + 25 + 121 = 278; Σxy = −45 − 21 − 1 − 1 − 15 − 55 = −138.
  3. r = −138 ÷ √(70 × 278) = −138 ÷ 139.50 = −0.99.
  4. (b) Yes: a very high negative correlation shows demand falls as price rises.
  5. (c) No: converting to paise is a change of scale; r is independent of scale.

Answer: (a) r ≈ −0.99; (b) yes, it supports the law of demand; (c) no change, since r is independent of scale.

Example 7: Finding a wrong D² · 2 marks · Short answerHarder exam level

Suppose the rank correlation for 10 pairs was calculated as 0.5. Later it was found that one difference in ranks was taken as 3 instead of 7. Find the correct rank correlation.

Try it first, then show the solutionSolution
  1. 0.5 = 1 − 6ΣD² ÷ 990 → ΣD² = 0.5 × 990 ÷ 6 = 82.5.
  2. Correct ΣD² = 82.5 − 9 + 49 = 122.5; r_s = 1 − 6 × 122.5 ÷ 990 = 1 − 0.742 = 0.26.

Answer: Correct r_s ≈ 0.26.

Case-study practice (Section C style)

Read the situation, then answer every part. In a school exam set on the board pattern this is a 4-mark question split into 2 + 1 + 1 marks.

Fertiliser and yield in five villages

Suppose an agricultural officer records fertiliser use (X, kg per hectare) and wheat yield (Y, quintals per hectare) in five villages: X 1, 2, 3, 4, 5 (in tens of kg); Y 2, 4, 5, 4, 5 (in tens of quintals). She wants to know whether more fertiliser goes with higher yield.

  1. (i) · 2 marks

    Calculate Σxy, Σx² and Σy².

    Answer

    Answer: X̄ = 3, Ȳ = 4; x = −2, −1, 0, 1, 2; y = −2, 0, 1, 0, 1; Σxy = 4 + 0 + 0 + 0 + 2 = 6; Σx² = 10; Σy² = 4 + 0 + 1 + 0 + 1 = 6.

    1 mark table, 1 mark sums.

  2. (ii) · 1 mark

    Find r and interpret it.

    Answer

    Answer: r = 6 ÷ √(10 × 6) = 6 ÷ 7.75 = 0.77: high positive correlation.

    1 mark.

  3. (iii) · 1 mark

    The officer concludes that 'fertiliser causes higher yield'. Comment.

    Answer

    Answer: Correlation shows association, not causation; villages using more fertiliser may also have better irrigation or seeds. A controlled comparison is needed.

    1 mark.

Where the marks are

How a typical answer is split into step marks. Show every step: a right final answer alone rarely earns full marks.

Spearman with a tie (2 marks) (2 marks)

StepMarks
Ranks with average rank for ties; ΣD²1
Correction factor and r_s1

Karl Pearson's r (4 marks) (4 marks)

StepMarks
Means and deviations1
Σx², Σy², Σxy2
r and interpretation1

Rank correlation with several ties (6 marks) (6 marks)

StepMarks
Ranks for X with ties1
Ranks for Y with ties1
D and ΣD²1
Correction factors1
Formula and value1
Interpretation1

Where students lose marks in Correlation

The slips examiners see most often, and what to write instead.

  • Mistake: Ranking one variable from highest and the other from lowest

    Opposite ranking reverses the sign of r_s.

    Do this: Use the same rule (highest = 1) for both.

    Usually costs: 2 marks.

  • Mistake: Forgetting the correction for tied ranks

    Without it, r_s is overstated.

    Do this: Add (m³ − m) ÷ 12 for every tie group in either series.

    Usually costs: 1 mark.

  • Mistake: Getting r greater than 1

    A sign of an arithmetic slip; r must lie between −1 and +1.

    Do this: Recheck Σx², Σy² (always positive) and Σxy.

    Usually costs: 1-2 marks.

  • Mistake: Interpreting correlation as causation

    Correlation shows only association.

    Do this: Say 'is associated with' and mention possible third factors.

    Usually costs: 1 mark.

Practice questions on Correlation

Write each answer on paper first. Open the hint only if you are stuck, and the answer only when you have finished.

  1. Q1 · 1 mark · MCQExam level

    If the points of a scatter diagram lie on a straight line falling from left to right, the correlation is:
    (a) perfect positive
    (b) perfect negative
    (c) zero
    (d) low negative

    Hint

    Exactly on a falling line.

    Answer

    (b) perfect negative.

  2. Q2 · 1 mark · Very short answerExam level

    Give one example each of positive and negative correlation from economics.

    Hint

    Income; price.

    Answer

    Positive: income and consumption (or price and supply). Negative: price and quantity demanded (or interest rate and investment).

  3. Q3 · 1 mark · Very short answerExam level

    Calculate Spearman's rank correlation when ΣD² = 30 and N = 10.

    Hint

    N³ − N = 990.

    Answer

    r_s = 1 − 180 ÷ 990 = 0.82.

  4. Q4 · 4 marks · Short answerHarder exam level

    Calculate Karl Pearson's r for X: 3, 5, 7, 9, 11 and Y: 15, 12, 10, 6, 2.

    Hint

    Means 7 and 9.

    Answer

    x = −4, −2, 0, 2, 4; y = 6, 3, 1, −3, −7; Σx² = 40; Σy² = 36 + 9 + 1 + 9 + 49 = 104; Σxy = −24 − 6 + 0 − 6 − 28 = −64. r = −64 ÷ √(40 × 104) = −64 ÷ 64.50 = −0.99.

  5. Q5 · 2 marks · Short answerHarder exam level

    State four properties of Karl Pearson's coefficient of correlation.

    Hint

    Range, origin, scale, symmetry.

    Answer

    It lies between −1 and +1; it is independent of change of origin; it is independent of change of scale; it is symmetric (r between X and Y equals r between Y and X). Also, r = 0 means no linear relationship.

  6. Q6 · 2 marks · Short answerHarder exam level

    Suppose Σdx = 0, Σdy = 0, Σdx² = 28, Σdy² = 32 and Σdxdy = 20 for 7 pairs (deviations from assumed means equal to the actual means). Find r.

    Hint

    Assumed = actual, so the simple formula applies.

    Answer

    r = 20 ÷ √(28 × 32) = 20 ÷ √896 = 20 ÷ 29.93 = 0.67: moderate positive correlation.

  7. Q7 · 4 marks · Short answerHOTS / competency

    Suppose three judges ranked 6 singers. Judges 1 and 2 have ΣD² = 50, judges 1 and 3 have ΣD² = 14, and judges 2 and 3 have ΣD² = 70. Which pair agrees most and which least?

    Hint

    N³ − N = 210.

    Answer

    r(1,2) = 1 − 300 ÷ 210 = −0.43; r(1,3) = 1 − 84 ÷ 210 = 0.60; r(2,3) = 1 − 420 ÷ 210 = −1.00. Judges 1 and 3 agree most (0.60); judges 2 and 3 have exactly opposite rankings (−1).

  8. Q8 · 2 marks · Short answerHarder exam level

    What is spurious correlation? Give an example.

    Hint

    Nonsense or chance.

    Answer

    A correlation that has no meaningful cause-and-effect basis, arising by chance or through a third variable. Example: sales of ice cream and the number of drowning cases both rise in summer; neither causes the other.

  9. Q9 · 6 marks · Long answerHOTS / competency

    'A high value of r between two variables proves that one causes the other.' Critically examine, with reference to the uses and limitations of correlation in economics.

    Hint

    Association vs causation; third factor; chance; reverse causation.

    Answer

    The statement is incorrect. Correlation measures how closely two variables move together, which is useful: it tests expected relationships (price and demand), helps prediction and guides policy. But a high r can arise from (1) a third factor affecting both (rain affects both umbrella sales and colds); (2) pure chance in small samples (spurious correlation); (3) reverse causation (does higher income cause more education, or education cause higher income?); (4) a mixture of influences. Also r measures only linear association; a strong curved relationship may give a low r. So economic theory and further analysis are needed before claiming causation.

  10. Q10 · 2 marks · Short answerHOTS / competency

    Suppose the rank correlation between two variables for 8 pairs is 0.75. Find ΣD².

    Hint

    Rearrange the formula; N³ − N = 504.

    Answer

    0.75 = 1 − 6ΣD² ÷ 504 → 6ΣD² = 0.25 × 504 = 126 → ΣD² = 21.

Test your recall

Answer in your head or on paper first, then open the card. Pulling an answer out of memory makes it stick far better than re-reading.

  1. 1.Range of r?Show answer

    −1 to +1.

  2. 2.Pearson's formula (actual means)?Show answer

    Σxy ÷ √(Σx² × Σy²).

  3. 3.Spearman's formula?Show answer

    1 − 6ΣD² ÷ (N³ − N).

  4. 4.Correction for a tie of m items?Show answer

    (m³ − m) ÷ 12.

  5. 5.Effect of change of scale on r?Show answer

    None.

  6. 6.Correlation implies causation?Show answer

    No; it shows association only.

Best order to study it

  1. Meaning, significance; correlation vs causation.
  2. Types and degrees.
  3. Scatter diagram.
  4. Karl Pearson's r: actual and assumed mean methods.
  5. Spearman's rank correlation: no ties, ties.
  6. Choosing and interpreting coefficients.

Quick revision checklist

The night before the exam: can you do each of these without looking?

  • Correlation: direction and degree of linear relationship; −1 ≤ r ≤ +1.
  • Positive (same direction), negative (opposite), linear or non-linear.
  • Scatter diagram: visual, no exact value.
  • r = Σxy ÷ √(Σx²Σy²); independent of origin and scale.
  • r_s = 1 − 6ΣD² ÷ (N³ − N); ties: average rank + (m³ − m)/12.
  • Correlation ≠ causation.

Correlation: frequently asked questions

Does r = 0 mean the variables are unrelated?

It means there is no linear relationship. The variables may still have a curved (non-linear) relationship, which a scatter diagram would reveal.

Why is r unaffected by change of origin and scale?

Because r is based on standardised deviations: subtracting a constant does not change deviations from the mean, and multiplying by a constant scales the numerator and denominator equally.

Can Spearman's coefficient be used for quantitative data?

Yes. Convert the values to ranks first. It is useful when the data contain extreme values or when only the order matters.

Based on: CISCE ISC 2028 Economics syllabus (Classes XI and XII); CISCE Regulations for the ISC Examination Year 2028 (Class XI internal examination)