Periodic Properties and Variations of Properties ICSE Class 10: Trends Explained
Updated 14 October 2026 · Fact-checked
Periodic properties are properties that repeat at regular intervals when elements are arranged by atomic number. ICSE Class 10 studies six of them: atomic size, metallic and non-metallic character, ionisation potential, electron affinity and electronegativity, explained using nuclear charge and the number of shells, for elements up to calcium.
What Periodic Properties and Variations of Properties is about
The modern periodic law says that the properties of elements are a periodic function of their atomic numbers. Elements with the same number of valence electrons fall in the same group (vertical column) and behave alike; elements with the same number of shells fall in the same period (horizontal row).
The CISCE 2027 syllabus asks for the definitions and the trends, in groups and in periods, of six properties: atomic size, metallic character, non-metallic character, ionisation potential, electron affinity and electronegativity. You are shown the whole modern periodic table, but questions are set only on elements up to period 4 as far as calcium (atomic number 20). Every explanation must use just two ideas, nuclear charge and number of shells; orbitals are not part of the course. The syllabus gives special attention to the alkali metals (group 1) and the halogens (group 17).
The whole chapter reduces to one picture. Across a period, the number of shells stays the same while the nuclear charge rises, so the outer electrons are pulled in harder. Down a group, a new shell is added each time, so the outer electrons sit further out and are held less firmly. Every trend follows from this. The CISCE syllabus numbers the groups 1 to 18; the older labels IA ... VIIA and 0 name the same columns.
Weightage: CISCE publishes no chapter or unit weightage for ICSE Chemistry. Periodic Properties and Variations of Properties is in the 1. Periodic Properties and variations of Properties – Physical and Chemical part of the 2027 syllabus and can be asked in both Section A and Section B of the 80-mark paper.Source: CISCE ICSE Chemistry (Science Paper 2) syllabus, examination year 2027
Key concepts
- Periods, groups and electronic configuration
Write the electronic configuration by shells (K, L, M, N) with at most 2, 8, 8 electrons in the first three shells for the first 20 elements; potassium (19) is 2, 8, 8, 1 and calcium (20) is 2, 8, 8, 2.
- Period number = number of occupied shells.
- Group number: for 1 or 2 valence electrons, group 1 or 2 (IA, IIA). For 3 to 7 valence electrons, group 13 to 17 (IIIA to VIIA), that is, add 10. A full outer shell (2 or 8) means group 18 (zero group).
- Valency for metals = valence electrons; for non-metals = 8 minus valence electrons.
Hydrogen (1 electron) is unusual: like group 1 it has one electron to lose, like group 17 it needs one electron to complete its shell, so it can be placed with either.
Worked example
An element X has atomic number 16. Write its electronic configuration and state its period, group and valency.
Try it first, then show the solutionSolution
- Fill shells: 2, 8, 6.
- Three shells are occupied, so period 3.
- Six valence electrons, so group 16 (VIA).
- It needs 2 more electrons for an octet, so valency 2.
Answer: 2, 8, 6; period 3; group 16 (VIA); valency 2 (it is sulphur).
- Atomic size (atomic radius)
Atomic size is the distance between the centre of the nucleus and the outermost shell of an atom.
- Across a period (left to right): decreases. The number of shells is the same, but the nuclear charge increases by one unit at each step, so the outer shell is pulled closer. Example: Na > Mg > Al > Si > P > S > Cl.
- Down a group: increases. A new shell is added at each step; this outweighs the rise in nuclear charge. Example: Li < Na < K.
Noble gases are usually left out of size comparisons across a period, because their size is measured in a different way.
Worked example
Arrange Mg, Na, Cl and Si in decreasing order of atomic size and give a reason.
Try it first, then show the solutionSolution
- All four are in period 3 (three shells).
- Nuclear charge: Na 11, Mg 12, Si 14, Cl 17.
- Greater nuclear charge with the same shells pulls the outer shell inwards.
Answer: Na > Mg > Si > Cl; nuclear charge rises across the period while the number of shells stays three.
- Ionisation potential (ionisation energy)
Ionisation potential is the energy needed to remove an electron from the outermost shell of an isolated gaseous atom to form a positive ion: .
- Across a period: increases, because the outer electron is held more tightly by a larger nuclear charge and a smaller atom.
- Down a group: decreases, because the outer electron is further from the nucleus and is shielded by more inner shells.
- Noble gases have the highest ionisation potential in their period, because a full outer shell is very stable.
Low ionisation potential means an atom loses electrons easily, so it is a strong metal and a good reducing agent.
Worked example
Which has the higher ionisation potential, sodium or potassium? Explain.
Try it first, then show the solutionSolution
- Both are in group 1.
- Potassium (2, 8, 8, 1) has four shells; sodium (2, 8, 1) has three.
- Potassium's outer electron is further from the nucleus and better shielded, so it is easier to remove.
Answer: Sodium has the higher ionisation potential.
- Electron affinity
Electron affinity is the energy released when an isolated gaseous atom gains an electron to form a negative ion: .
- Across a period: increases, because a smaller atom with a larger nuclear charge attracts the added electron more strongly. The halogens have the highest electron affinity in each period.
- Down a group: generally decreases, because the incoming electron enters a shell further from the nucleus.
- Noble gases: about zero, because a full outer shell has no tendency to accept another electron.
One point beyond the basic rule: chlorine releases slightly more energy than fluorine on gaining an electron, because fluorine's very small outer shell is already crowded. If a question simply asks for the general trend, give the general trend.
Worked example
Among Mg, Ar, Li and Cl, which has the highest electron affinity, and why does argon not?
Try it first, then show the solutionSolution
- Halogens need only one electron to complete the octet, so they release the most energy on gaining one.
- Argon already has a stable octet; it has almost no tendency to gain an electron.
Answer: Chlorine; argon's full outer shell gives it an electron affinity of about zero.
- Electronegativity
Electronegativity is the tendency of an atom in a molecule to attract the shared pair of electrons towards itself. Do not confuse it with electron affinity, which is about an isolated atom gaining an electron.
- Across a period: increases (larger nuclear charge, smaller atom).
- Down a group: decreases (outer shell further out).
- Fluorine is the most electronegative element of all; in period 3, chlorine is the most electronegative (argon is not given a value, since it does not normally form bonds).
Electronegativity difference decides bond type: a large difference (Na and Cl) gives an ionic bond; a small difference (H and Cl) gives a polar covalent bond; no difference (Cl and Cl) gives a non-polar bond.
Worked example
Name the most electronegative element of period 2 and of period 3.
Try it first, then show the solutionSolution
- Electronegativity rises to the right of a period, stopping before the noble gas.
- Period 2 ends with F before Ne; period 3 ends with Cl before Ar.
Answer: Fluorine (period 2) and chlorine (period 3).
- Metallic and non-metallic character
Metallic character is the tendency of an atom to lose electrons and form a positive ion; non-metallic character is the tendency to gain electrons and form a negative ion.
- Across a period: metallic character decreases and non-metallic character increases (atoms hold electrons harder). Period 3 runs from the very metallic Na to the non-metal Cl, with silicon a metalloid in between.
- Down a group: metallic character increases (outer electron easier to lose), non-metallic character decreases.
The same idea explains oxides: metals form basic oxides (, ), non-metals form acidic oxides (, ), and some metals near the dividing line form amphoteric oxides (, ).
Worked example
X, Y and Z are three metals in the same group in that order from top to bottom. Which is the strongest reducing agent?
Try it first, then show the solutionSolution
- A reducing agent gives away electrons.
- Down a group, the outer electron is further from the nucleus, so it is lost more easily.
- Z is at the bottom, so it has the largest atom and the lowest ionisation potential.
Answer: Z, the largest atom with the lowest ionisation potential.
- Alkali metals and halogens: two families compared
Alkali metals (group 1: Li, Na, K) have one valence electron. Down the group, atomic size increases and ionisation potential decreases, so reactivity increases: lithium reacts steadily with water, sodium vigorously, potassium so violently that the hydrogen catches fire.
Halogens (group 17: F, Cl, then Br and I lower down) have seven valence electrons and react by gaining one. Down the group, atomic size increases, so the pull on an incoming electron weakens and reactivity decreases. A more reactive halogen therefore displaces a less reactive one from its salt solution:
So the two families show opposite reactivity trends down the group, for the same underlying reason (bigger atom, outer shell further out).
Worked example
Why does reactivity increase down group 1 but decrease down group 17?
Try it first, then show the solutionSolution
- Group 1 metals react by losing an electron; a larger atom loses it more easily.
- Group 17 non-metals react by gaining an electron; a larger atom attracts it less strongly.
- Both families get larger down the group.
Answer: Increasing size helps electron loss (group 1) but hinders electron gain (group 17).
Chemistry in real life: Periodic Properties and Variations of Properties
Each concept, met in an everyday situation. Read the situation, try the problem, then check the solution. The one-line hook is what to remember.
Reactivity of alkali metals
Suppose a laboratory assistant finds three unlabelled jars of soft metal stored under kerosene and knows only that they are lithium, sodium and potassium. She drops a tiny piece of each into separate troughs of water behind a safety screen.
Predict how the three reactions differ, name the gas given off, and explain the order using periodic properties.
Try it first, then show the solutionSolution
- All three react with water to form an alkali and hydrogen, for example .
- Down group 1, the atomic size increases and the ionisation potential decreases.
- So potassium loses its outer electron most easily, then sodium, then lithium.
- The piece that reacts most violently (the hydrogen may catch fire) is potassium; the slowest is lithium.
Answer: Reactivity: K > Na > Li; the gas is hydrogen; lower ionisation potential down the group makes electron loss easier.
Memory hook: Down group 1, the outer electron is further away, so it leaves sooner and the splash is bigger.
Halogen displacement
Suppose a water-treatment chemist bubbles chlorine through a sample of sodium bromide solution taken from a salt lake and sees the colourless liquid turn orange-brown.
Explain the colour change and write the balanced equation. Would iodine solution do the same to sodium bromide?
Try it first, then show the solutionSolution
- Chlorine is higher in group 17 than bromine, so it is smaller and gains electrons more readily.
- So chlorine takes the electron from bromide ions and frees bromine, which is orange-brown: .
- Iodine is below bromine, so it is less reactive and cannot displace bromine.
Answer: Bromine is displaced by the more reactive chlorine; iodine would not react.
Memory hook: A halogen higher up pushes out one lower down.
Electronegativity and bond type
Suppose you are designing a quiz card that asks players to sort NaCl, HCl and Cl₂ into 'ionic', 'polar covalent' and 'non-polar covalent' by looking only at where the elements sit in the periodic table.
Sort the three and give the reasoning a player should use.
Try it first, then show the solutionSolution
- Na (far left, low electronegativity) and Cl (high) differ a lot, so sodium transfers an electron: ionic.
- H and Cl differ moderately; the electrons are shared but pulled towards Cl: polar covalent.
- Cl and Cl are identical, so the pair is shared equally: non-polar covalent.
Answer: NaCl ionic; HCl polar covalent; Cl₂ non-polar covalent.
Memory hook: The bigger the electronegativity gap, the more one-sided the bond.
Topics in this chapter
- Periods, Groups and Electronic ConfigurationComing soon
- Ionisation Potential, Electron Affinity and ElectronegativityComing soon
- Atomic Size and Metallic CharacterComing soon
- Ionisation Potential, Electron Affinity and Electronegativity
- Periodicity, Atomic Size and Metallic Character
Periodic Properties and Variations of Properties formula sheet
- Trend across a period (left to right)
- Same number of shells; nuclear charge increases.
- Trend down a group
- A new shell is added at each step.
- Ionisation potential
- Energy is absorbed.
- Electron affinity
- Energy is released.
- Group from valence electrons
- Full outer shell: group 18 (0).
- Valency
- v = number of valence electrons.
Periodic Properties and Variations of Properties: diagrams to practise
Practise each one on paper: draw it from the checklist, then tick off every label.
Trend arrows on a periodic table outline
To show trends in atomic size, ionisation potential and electronegativity in a revision answer or a labelled sketch.
Draw
- Draw an outline grid of 8 columns (groups 1, 2, 13-18) and 4 rows (periods 1-4).
- Draw a horizontal arrow along the top pointing right, labelled 'IP, EA, EN, non-metallic character increase; size decreases'.
- Draw a vertical arrow along the left side pointing down, labelled 'size and metallic character increase; IP, EA, EN decrease'.
- Shade the top right (fluorine) as most non-metallic and the bottom left (potassium, in this course) as most metallic.
Label
- Period
- Group
- Increasing nuclear charge
- Increasing number of shells
Watch out: Keep noble gases as a separate column and mark them 'highest IP, EA about zero'.
How the board asks Periodic Properties and Variations of Properties
The question patterns to expect, and the method that works for each.
| Question type | How it is asked | Method |
|---|---|---|
| MCQ on a trend or an exception | Section A, Question 1: which element has the largest size, highest ionisation potential or highest electron affinity in a list; why a noble gas has a high ionisation potential. | Locate each element (period, group) first, then apply the trend. Check for a noble gas in the list. |
| Arrange in order | Section B: arrange three or four elements in increasing or decreasing order of a property, often mixed with other orders in the same question. | Read the word 'increasing' or 'decreasing' twice; write the symbols with < or > in the direction asked. |
| Table with letters | A partial periodic table with letters in place of symbols; state the valency, the formula of a compound, the most metallic element, or the element showing catenation. | Answer only with the letters given; never identify the element. Metal first in a formula. |
| Give reasons | Short answers: why atomic size decreases across a period, why ionisation potential of noble gases is high, why fluorine is more electronegative than chlorine. | Name the cause (nuclear charge or number of shells) and the effect on the outer electrons. |
| Identify from configuration | Given atomic number or configuration, state the period, group, valency, or formula with another element. | Write the configuration by shells; count shells for the period and outer electrons for the group. |
Tricks to remember Periodic Properties and Variations of Properties
Short memory aids. Say each one aloud once, then use it on a question the same day.
Across: the nucleus wins
Across a period, the shells stay the same and the nucleus gets stronger, so everything that depends on 'holding on' (IP, EA, EN, non-metallic character) goes up, and size and metallic character go down.
Use it when: Any across-the-period trend in one sentence.
Down: the shell wins
Down a group, a new shell is added. Bigger atom, looser grip: size and metallic character up, IP, EA and EN down.
Use it when: Any down-the-group trend.
Bottom-left, top-right
The most metallic element is at the bottom left, the most non-metallic at the top right (fluorine), noble gases aside.
Use it when: Quickly spotting the extreme element in a list.
Affinity is alone, negativity is in a bond
Electron Affinity: an Atom Alone gains an electron. ElectroNegativity: a Neighbour is sharing.
Use it when: Not mixing up the two definitions.
Periodic Properties and Variations of Properties: board-level solved questions
Ordered from board level to HOTS. Cover the solution, write your own, then compare step by step.
Example 1: Noble gas ionisation potential · 1 mark · MCQBoard level
Argon has the highest ionisation potential in period 3 because:
(a) it has the largest atomic size in the period
(b) its outermost shell is completely filled
(c) it readily gains an electron
(d) it has the fewest shells
Try it first, then show the solutionSolution
- A complete octet is very stable, so removing an electron from it needs the most energy.
Answer: (b)
Example 2: Trend in a group · 1 mark · Assertion-reasonHarder board level
Assertion (A): Potassium is a stronger reducing agent than sodium.
Reason (R): Potassium has a smaller nuclear charge than sodium.
(a) Both (A) and (R) are true, and (R) is the correct explanation for (A).
(b) Both (A) and (R) are true, but (R) is not the correct explanation for (A).
(c) (A) is true and (R) is false.
(d) (A) is false and (R) is true.
Try it first, then show the solutionSolution
- (A) is true: potassium loses its outer electron more easily.
- (R) is false: potassium (19) has a larger nuclear charge than sodium (11); its outer electron is easier to lose because it is in a fourth shell, further from the nucleus.
Answer: (c)
Example 3: Identify from position · 3 marks · Short answerBoard level
Element P is in period 3 and group 2; element Q is in period 2 and group 17. (a) Write the electronic configurations. (b) Write the formula of the compound they form and state the type of bond.
Try it first, then show the solutionSolution
- P: three shells with 2 outer electrons: 2, 8, 2 (valency 2).
- Q: two shells with 7 outer electrons: 2, 7 (valency 1).
- Criss-cross valencies, metal first: .
- P loses electrons and Q gains them, so the bond is electrovalent (ionic).
Answer: P: 2, 8, 2; Q: 2, 7; PQ₂, electrovalent.
Example 4: Three orders in one question · 3 marks · Short answerHarder board level
Arrange as instructed:
(a) O, Li, B, F (increasing atomic size)
(b) Ca, Mg, Be (increasing ionisation potential)
(c) S, Al, Cl, Na (increasing electronegativity)
Try it first, then show the solutionSolution
- (a) Period 2, size falls left to right: F < O < B < Li.
- (b) Group 2, ionisation potential falls down the group: Ca < Mg < Be.
- (c) Period 3, electronegativity rises left to right: Na < Al < S < Cl.
Answer: (a) F < O < B < Li (b) Ca < Mg < Be (c) Na < Al < S < Cl
Example 5: Letters in a table · 4 marks · Case-basedHarder board level
In a partial periodic table, A is in group 1, period 3; B is in group 14, period 2; C is in group 17, period 3; D is in group 18, period 2. Using only these letters: (a) which is the most metallic? (b) which shows catenation? (c) which has zero electron affinity? (d) give the formula of the compound of A and C.
Try it first, then show the solutionSolution
- (a) Group 1 is at the far left: A.
- (b) Group 14, period 2 is the carbon position, and catenation is a property of carbon: B.
- (c) Group 18 has a full outer shell: D.
- (d) A valency 1, C valency 1: AC.
Answer: (a) A (b) B (c) D (d) AC
Example 6: Reason questions · 2 marks · Short answerBoard level
Give reasons: (a) The atomic size of chlorine is smaller than that of sodium. (b) Fluorine is more electronegative than chlorine.
Try it first, then show the solutionSolution
- (a) Both have three shells, but chlorine has a nuclear charge of 17 against sodium's 11, so its outer shell is pulled closer.
- (b) Fluorine has only two shells, so its nucleus is closer to the bonding pair and attracts it more strongly.
Answer: (a) Same shells, greater nuclear charge. (b) Fewer shells, smaller atom.
Example 7: Unknown elements by configuration · 3 marks · Short answerHarder board level
Elements X, Y and Z have atomic numbers 9, 17 and 19. (a) Which two are in the same group? (b) Which is the most reactive non-metal? (c) Which forms a basic oxide? Explain each answer.
Try it first, then show the solutionSolution
- Configurations: X 2, 7; Y 2, 8, 7; Z 2, 8, 8, 1.
- (a) X and Y each have 7 valence electrons: group 17.
- (b) X is smaller (two shells), so it gains an electron more readily: X.
- (c) Z has one valence electron, a metal: its oxide is basic.
Answer: (a) X and Y (b) X (c) Z
Example 8: HOTS: a mystery period · 4 marks · Long answerHOTS / competency
An element R has three shells. It forms an oxide R₂O₃ that reacts with both hydrochloric acid and sodium hydroxide. (a) State the group and atomic number of R. (b) Name the type of oxide. (c) Is R more or less metallic than the element just before it in the period? Explain.
Try it first, then show the solutionSolution
- Oxide R₂O₃ means valency 3, so 3 valence electrons: group 13.
- Three shells: configuration 2, 8, 3, atomic number 13 (aluminium).
- An oxide reacting with both acid and alkali is amphoteric.
- The element before it, magnesium, has fewer protons holding its outer electrons, so it loses electrons more easily. R is less metallic.
Answer: (a) Group 13, atomic number 13 (b) amphoteric (c) less metallic, because metallic character decreases across a period.
Case-study practice (Section B style)
Read the situation, then answer every part. In the board paper this is a 4-mark question split into 2 + 1 + 1 marks.
Reading period 3 data
Suppose a student collects the values below for period 3 from a data book (units omitted) and wants to explain them.
| Element | Na | Mg | Al | Si | P | S | Cl |
|---|---|---|---|---|---|---|---|
| Atomic radius | 186 | 160 | 143 | 117 | 110 | 104 | 99 |
| Electronegativity | 0.9 | 1.2 | 1.5 | 1.8 | 2.1 | 2.5 | 3.0 |
(i) · 2 marks
State the trend in atomic radius shown by the data and the reason for it.
Answer
Answer: Radius decreases from Na to Cl, because the nuclear charge increases while the number of shells stays three.
1 mark for the trend, 1 mark for the reason in terms of nuclear charge and shells.
(ii) · 1 mark
Which element in the table forms the most ionic bond with chlorine? Use the data to justify.
Answer
Answer: Sodium: the electronegativity gap with chlorine (3.0 - 0.9 = 2.1) is the largest.
(iii) · 1 mark
Predict, with a reason, whether argon's ionisation potential is higher or lower than chlorine's.
Answer
Answer: Higher: argon has a complete octet, which is very stable.
Placing hydrogen
Suppose a class is debating where hydrogen (atomic number 1) belongs. One group says group 1; another says group 17.
(i) · 2 marks
Give one argument for each group.
Answer
Answer: Group 1: one electron in its only shell, which it can lose to form H⁺. Group 17: needs one more electron to complete its shell (duplet), forming H⁻ with very reactive metals, and exists as diatomic molecules like the halogens.
(ii) · 1 mark
Name the period of hydrogen.
Answer
Answer: Period 1 (one shell).
Where the marks are
How a typical answer is split into step marks. Show every step: a right final answer alone rarely earns full marks.
State the period and group of an element with atomic number 15, and write the formula of its hydride. (2 marks) (2 marks)
| Step | Marks |
|---|---|
| Configuration 2, 8, 5: period 3, group 15 (VA) | 1 |
| Valency 8 - 5 = 3: hydride (phosphine-type) | 1 |
Arrange in increasing order: (a) Na, K, Li (ionisation potential); (b) N, F, O (electronegativity); (c) Cl, P, Na (atomic size). (3 marks) (3 marks)
| Step | Marks |
|---|---|
| K < Na < Li | 1 |
| N < O < F | 1 |
| Cl < P < Na | 1 |
Explain why (a) atomic size increases down a group, (b) ionisation potential increases across a period, (c) noble gases have nearly zero electron affinity, (d) the most metallic element of period 3 is sodium. (4 marks) (4 marks)
| Step | Marks |
|---|---|
| New shell added at each step down the group, so the outer electrons are further from the nucleus | 1 |
| Greater nuclear charge with the same number of shells holds the outer electrons more tightly | 1 |
| The outer shell is already complete and stable, so there is no tendency to gain an electron | 1 |
| Sodium has one valence electron and the lowest nuclear charge in period 3, so it loses that electron most easily | 1 |
Where students lose marks in Periodic Properties and Variations of Properties
The slips examiners see most often, and what to write instead.
Mistake: Calling the noble gas configuration unstable
CISCE examiners' comments, 2024: when asked why neon has the highest ionisation potential in period 2, candidates chose 'unstable electronic configuration'.
Wrong working
Neon has the maximum ionisation potential because its configuration is unstable.
Right working
Neon's outer shell is completely filled (2, 8), a very stable arrangement, so the most energy is needed to remove an electron.
Do this: A full shell is the most stable arrangement: high ionisation potential, almost zero electron affinity.
Usually costs: 1 mark (MCQ).
Mistake: Giving a noble gas the highest electron affinity
CISCE examiners' comments, 2024: candidates chose argon or lithium for the highest electron affinity instead of bromine, forgetting that inert gases have almost no electron affinity.
Wrong working
Electron affinity is highest for Ar because it is at the end of the period.
Right working
Electron affinity is highest for the halogen; the noble gas has none.
Do this: Electron affinity and electronegativity peak at group 17, not group 18; ionisation potential peaks at group 18.
Usually costs: 1 mark.
Mistake: Linking a small atom with the best reducing agent
CISCE examiners' comments, 2025: for three metals in a group, candidates picked the smallest atom as the best reducing agent.
Wrong working
X has the smallest radius, so it is the best reducing agent.
Right working
Z, the largest atom, loses its outer electron most easily, so it is the best reducing agent.
Do this: Reducing agent = electron giver = large metal atom with low ionisation potential.
Usually costs: 1 mark.
Mistake: Using the wrong symbol or direction in an order
CISCE examiners' comments, 2024: candidates reversed the order or used the wrong < or > signs when arranging elements.
Wrong working
Increasing ionisation potential: Li > Na > K
Right working
Increasing ionisation potential: K < Na < Li
Do this: Write 'increasing' with < from left to right; check the first element is the smallest value.
Usually costs: 1 mark per order.
Mistake: Roman numerals for periods and confusing valency with valence electrons
CISCE examiners' comments, 2025: candidates wrote period III instead of 3, gave valency 5 for a group 15 element, and wrote the name instead of the formula.
Wrong working
Element with 2, 8, 5: period III, valency 5.
Right working
Period 3, valency 3 (8 - 5).
Do this: Periods in Arabic numerals; non-metal valency = 8 minus valence electrons.
Usually costs: 1 mark each.
Mistake: Mixing up ionisation potential and electronegativity
CISCE examiners' comments, 2025: asked for the highest ionisation potential in Ne, O and F, candidates wrote fluorine.
Wrong working
Highest ionisation potential among Ne, O, F: F (most electronegative).
Right working
Ne: a noble gas has the highest ionisation potential in its period.
Do this: Ionisation potential includes noble gases; electronegativity and electron affinity do not.
Usually costs: 1 mark.
Practice questions on Periodic Properties and Variations of Properties
Write each answer on paper first. Open the hint only if you are stuck, and the answer only when you have finished.
Q1 · 1 mark · MCQBoard level
Which of these has the smallest atomic size?
(a) Na
(b) Mg
(c) S
(d) ClHint
All are in period 3.
Answer
(d) Cl
Q2 · 1 mark · MCQBoard level
The element with configuration 2, 8, 8, 2 is in:
(a) period 2, group 8
(b) period 4, group 2
(c) period 3, group 2
(d) period 2, group 2Hint
Count shells and outer electrons.
Answer
(b) period 4, group 2 (calcium).
Q3 · 1 mark · MCQHarder board level
Statement I: Electronegativity of chlorine is greater than that of sulphur.
Statement II: Chlorine has a greater nuclear charge than sulphur but the same number of shells.
(a) Both statements are true, and II explains I.
(b) Both statements are true, but II does not explain I.
(c) I is true, II is false.
(d) I is false, II is true.Hint
Same period.
Answer
(a)
Q4 · 1 mark · Assertion-reasonHarder board level
Assertion (A): Fluorine is the most reactive halogen.
Reason (R): Fluorine has the largest atomic size in group 17.
(a) Both (A) and (R) are true, and (R) is the correct explanation for (A).
(b) Both (A) and (R) are true, but (R) is not the correct explanation for (A).
(c) (A) is true and (R) is false.
(d) (A) is false and (R) is true.Hint
Where is fluorine in the group?
Answer
(c): fluorine is the smallest halogen, which is why it gains an electron most readily.
Q5 · 3 marks · Very short answerBoard level
Name: (a) the alkali metal in period 4; (b) the most electronegative element of period 3; (c) the element with configuration 2, 8, 6.
Hint
Elements 1-20.
Answer
(a) Potassium (b) Chlorine (c) Sulphur
Q6 · 3 marks · Short answerBoard level
An element has atomic number 12. (a) Is it a metal or a non-metal? (b) Write the formula of its oxide and its chloride. (c) Is its oxide acidic or basic?
Hint
Configuration 2, 8, 2.
Answer
(a) Metal (b) MgO-type: XO; chloride XCl₂ (c) Basic
Q7 · 3 marks · Short answerHarder board level
Arrange: (a) Be, Mg, Ca (increasing metallic character); (b) Li, C, N, F (decreasing atomic size); (c) Cl, F (increasing ionisation potential).
Hint
Check the direction of each.
Answer
(a) Be < Mg < Ca (b) Li > C > N > F (c) Cl < F
Q8 · 4 marks · Short answerHarder board level
Elements A, B and C have atomic numbers 3, 11 and 19. (a) Which property is the same for all three? (b) Which has the highest ionisation potential? (c) Which reacts most vigorously with water? Write the equation for that reaction using its symbol.
Hint
Group 1.
Answer
(a) One valence electron (valency 1, group 1). (b) A (lithium, smallest). (c) C (potassium): .
Q9 · 2 marks · Short answerHarder board level
Explain why the ionisation potential of magnesium is greater than that of sodium, but less than that of beryllium.
Hint
One across, one down.
Answer
Mg has a greater nuclear charge than Na with the same three shells, so it holds its outer electrons more tightly. Be has only two shells, so its outer electrons are closer to the nucleus than Mg's.
Q10 · 3 marks · Short answerHarder board level
Bromine water is added to (i) potassium chloride solution and (ii) potassium iodide solution. State what you observe in each and write the equation where a reaction occurs.
Hint
A halogen displaces only those below it.
Answer
(i) No change: bromine is less reactive than chlorine. (ii) The solution turns brown as iodine is set free: .
Q11 · 3 marks · Short answerHOTS / competency
Element Y forms the ion Y²⁻ with the configuration 2, 8, 8. (a) Find the atomic number of Y. (b) State its period and group. (c) Compare its atomic size with that of the element after it in the same period.
Hint
The ion has 2 extra electrons.
Answer
(a) 18 - 2 = 16 (b) Period 3, group 16 (c) Y is larger than the next element (chlorine), which has one more unit of nuclear charge and the same number of shells.
Q12 · 2 marks · Short answerHOTS / competency
A student says 'Since chlorine has a higher electron affinity than fluorine, chlorine must be more electronegative.' Is the student right? Explain.
Hint
Two different properties.
Answer
No. Electronegativity concerns an atom pulling a shared pair in a molecule; fluorine, being smaller, does this most strongly and is the most electronegative element. Electron affinity concerns an isolated atom, where fluorine's crowded small shell slightly lowers the energy released.
Test your recall
Answer in your head or on paper first, then open the card. Pulling an answer out of memory makes it stick far better than re-reading.
1.Define ionisation potential.Show answer
The energy needed to remove an electron from the outermost shell of an isolated gaseous atom.
2.Define electron affinity.Show answer
The energy released when an isolated gaseous atom gains an electron to form a negative ion.
3.Define electronegativity.Show answer
The tendency of an atom in a molecule to attract the shared electron pair towards itself.
4.How does atomic size change across a period?Show answer
It decreases, because nuclear charge increases while the number of shells stays the same.
5.Most electronegative element?Show answer
Fluorine.
6.Most metallic element up to calcium?Show answer
Potassium.
7.Electronic configuration of calcium?Show answer
2, 8, 8, 2.
8.How does reactivity change down the halogen group?Show answer
It decreases.
9.Which element can be placed in both group 1 and group 17?Show answer
Hydrogen.
Best order to study it
- Write the configurations of elements 1 to 20 until you can do it without thinking.
- Learn the two causes: nuclear charge (across) and number of shells (down).
- Learn the six definitions word for word, with the difference between electron affinity and electronegativity.
- Practise ordering questions and the noble-gas exceptions.
- Finish with letter-table questions and the alkali metal and halogen families.
Quick revision checklist
The night before the exam: can you do each of these without looking?
- Can you state the period, group and valency of any element up to calcium from its atomic number?
- Can you give all six trends across a period and down a group, with a reason for each?
- Do you know why noble gases have the highest ionisation potential but almost zero electron affinity?
- Can you explain why reactivity increases down group 1 but decreases down group 17?
- Can you write a halogen displacement equation, balanced?
- Can you answer a letter-table question without naming the elements?
Periodic Properties and Variations of Properties: frequently asked questions
Which elements can be asked in the ICSE 2027 Chemistry paper for periodic properties?
The 2027 syllabus says you study the modern periodic table up to period 4, and no questions are set on elements beyond calcium (atomic number 20). Know elements 1 to 20 well.
Do I need orbitals (s, p, d) to explain trends?
No. CISCE asks for explanations in terms of nuclear charge and shells, not orbitals.
Should I write group numbers as IA-VIIA or 1-18?
The CISCE syllabus uses groups 1 to 18, so use those numbers; IA-VIIA and 0 are older labels for the same columns. Be consistent within an answer.
Is electron affinity the same as electronegativity?
No. Electron affinity is energy released when an isolated atom gains an electron; electronegativity is how strongly an atom in a molecule pulls a shared pair.
Why does the noble gas not have an electronegativity value?
Noble gases have complete outer shells and do not normally form bonds, so they are not given values in this comparison.
Based on: CISCE ICSE 2027 Chemistry (Science Paper 2) syllabus; CISCE ICSE 2027 Chemistry (Science Paper 2) specimen question paper and marking scheme; CISCE Analysis of Pupil Performance, ICSE Chemistry (Science Paper 2), 2025; CISCE Analysis of Pupil Performance, ICSE Chemistry (Science Paper 2), 2024