Chemical Bonding ICSE Class 10: Electrovalent, Covalent and Coordinate Bonds
Updated 14 October 2026 · Fact-checked
A chemical bond holds atoms together so that each reaches a stable outer shell. An electrovalent bond forms by transfer of electrons, as in NaCl; a covalent bond by sharing a pair, as in Cl₂ or H₂O; a coordinate bond by sharing a pair given by one atom only, as in the ammonium and hydronium ions.
What Chemical Bonding is about
Atoms combine to reach a stable duplet (2 electrons in the first shell, like helium) or octet (8 in the outer shell, like neon or argon). They do it in three ways, and the CISCE 2027 syllabus asks for each with electron dot structures:
1. Electrovalent (ionic) bonding: a metal transfers electrons to a non-metal. The syllabus names NaCl, MgCl₂ and CaO.
2. Covalent bonding: two non-metals share electron pairs. Non-polar examples named are H₂, Cl₂, O₂, N₂, CCl₄ and CH₄; polar examples are HCl, NH₃ and H₂O.
3. Coordinate bonding: one atom provides both electrons of the shared pair. The syllabus asks for the hydronium ion (H₃O⁺) and the ammonium ion (NH₄⁺), explained by the lone pair on oxygen in water and on nitrogen in ammonia.
You also need the characteristic properties of electrovalent and covalent compounds (state, melting and boiling points, conductivity, behaviour in solution and when molten) and a side-by-side comparison. The properties link to the Electrolysis chapter: ionic compounds conduct when molten or dissolved because their ions are then free to move.
Weightage: CISCE publishes no chapter or unit weightage for ICSE Chemistry. Chemical Bonding is in the 2. Chemical Bonding part of the 2027 syllabus and can be asked in both Section A and Section B of the 80-mark paper.Source: CISCE ICSE Chemistry (Science Paper 2) syllabus, examination year 2027
Key concepts
- Why atoms bond: duplet and octet
Noble gases rarely react because their outer shells are full (helium 2; neon 2, 8; argon 2, 8, 8). Other atoms gain, lose or share electrons to reach the same arrangement.
- A metal with 1, 2 or 3 outer electrons loses them to form a cation (Na⁺, Mg²⁺, Ca²⁺).
- A non-metal with 5, 6 or 7 outer electrons gains to form an anion (Cl⁻, O²⁻) when it meets a metal, or shares electrons when it meets another non-metal.
The charge on an ion equals the number of electrons lost (positive) or gained (negative).
Worked example
Write the electronic configurations of Mg, Mg²⁺, O and O²⁻ (atomic numbers 12 and 8).
Try it first, then show the solutionSolution
- Mg: 2, 8, 2; losing 2 electrons gives Mg²⁺: 2, 8.
- O: 2, 6; gaining 2 electrons gives O²⁻: 2, 8.
- Both ions now have the neon arrangement.
Answer: Mg 2, 8, 2; Mg²⁺ 2, 8; O 2, 6; O²⁻ 2, 8.
- Electrovalent bonding: NaCl, MgCl₂, CaO
An electrovalent bond is the electrostatic attraction between oppositely charged ions formed by transfer of electrons from a metal to a non-metal.
- NaCl: Na (2, 8, 1) gives 1 electron to Cl (2, 8, 7). Ions: Na⁺ (2, 8) and Cl⁻ (2, 8, 8).
- MgCl₂: Mg (2, 8, 2) gives 1 electron to each of two Cl atoms. Ions: Mg²⁺ and 2Cl⁻.
- CaO: Ca (2, 8, 8, 2) gives 2 electrons to O (2, 6). Ions: Ca²⁺ (2, 8, 8) and O²⁻ (2, 8).
In a dot structure, show the metal's electrons as crosses and the non-metal's as dots, draw an arrow for each transferred electron, then write each ion in square brackets with its charge outside.
Worked example
Explain the formation of magnesium chloride by electron transfer. Write the formula and state the charges.
Try it first, then show the solutionSolution
- Mg has 2 outer electrons and needs to lose both.
- Each Cl atom has 7 and needs 1 more, so two Cl atoms are needed.
- Mg gives one electron to each Cl: Mg²⁺ and two Cl⁻ ions.
- Total positive charge 2+ balances total negative charge 2 × 1- = 2-.
Answer: MgCl₂: one Mg²⁺ ion and two Cl⁻ ions.
- Properties of electrovalent compounds
- State: hard crystalline solids at room temperature, because strong electrostatic forces hold the ions in a lattice.
- Melting and boiling points: high, as much energy is needed to break the lattice.
- Conductivity: do not conduct electricity as solids (ions are fixed), but do conduct when molten or in aqueous solution, because the ions are then free to move. This is why they are electrolytes.
- Solubility: usually soluble in water, insoluble in organic solvents such as kerosene or benzene.
- Dissociation: ions already exist in the solid; water or heat only frees them: .
Worked example
Solid sodium chloride does not conduct electricity, but molten sodium chloride does. Explain.
Try it first, then show the solutionSolution
- Solid NaCl consists of Na⁺ and Cl⁻ ions locked in a crystal lattice.
- On melting, the lattice breaks down and the ions become mobile.
- Moving ions carry the current.
Answer: Ions are fixed in the solid but free to move in the melt.
- Non-polar covalent bonding
A covalent bond is formed by mutual sharing of one or more electron pairs between two non-metal atoms. One shared pair is a single bond, two a double bond, three a triple bond.
- H₂: H•×H, one shared pair; each H gets a duplet.
- Cl₂: one shared pair; each Cl has 3 lone pairs.
- O₂: two shared pairs (double bond); each O has 2 lone pairs.
- N₂: three shared pairs (triple bond); each N has 1 lone pair.
- CH₄: carbon shares one pair with each of four H atoms; no lone pairs on C.
- CCl₄: four C–Cl single bonds; each Cl keeps 3 lone pairs.
When identical atoms share, the pair is shared equally: non-polar. CH₄ and CCl₄ are non-polar molecules because their four bonds are arranged symmetrically (tetrahedrally), so any pulls cancel.
Worked example
How many shared pairs and lone pairs are there in a nitrogen molecule?
Try it first, then show the solutionSolution
- N has 5 outer electrons and needs 3 more.
- Each N shares 3 electrons: 3 shared pairs (a triple bond).
- Each N keeps 2 unshared electrons: 1 lone pair each.
Answer: 3 shared pairs and 2 lone pairs (one on each N).
- Polar covalent bonding: HCl, H₂O, NH₃
When two different atoms share electrons, the more electronegative atom pulls the shared pair towards itself. It gets a partial negative charge (δ−) and the other atom a partial positive charge (δ+). The bond is polar covalent.
- HCl: H shares 1 pair with Cl; Cl (3 lone pairs) is δ−, H is δ+.
- H₂O: O shares one pair with each H; O keeps 2 lone pairs; O is δ−, each H δ+. The molecule is bent, so it is polar.
- NH₃: N shares one pair with each of three H atoms; N keeps 1 lone pair; N is δ−.
Polar covalent compounds such as HCl can ionise in water even though they contain no ions as pure substances.
Worked example
Why is HCl described as a polar covalent molecule and not an ionic compound?
Try it first, then show the solutionSolution
- H and Cl are both non-metals, so they share a pair rather than transfer an electron.
- Cl is more electronegative, so the shared pair is closer to Cl.
- This gives partial charges (δ+ on H, δ− on Cl), not full ionic charges.
Answer: Electrons are shared unequally: polar covalent.
- Properties of covalent compounds and the comparison
Covalent compounds exist as separate molecules held together by weak forces (van der Waals forces) between molecules, so:
- State: gases, liquids or soft solids (CH₄ and HCl gases, H₂O and CCl₄ liquids).
- Melting and boiling points: low, since only weak intermolecular forces must be overcome.
- Conductivity: poor conductors of heat and electricity; they contain no free ions. Polar ones such as HCl ionise in water and then conduct: .
- Solubility: generally soluble in organic solvents, mostly insoluble in water (polar ones like HCl and NH₃ are exceptions).
Property Electrovalent Covalent Formed by transfer of electrons sharing of electrons Particles ions molecules State crystalline solids gases, liquids, soft solids m.p./b.p. high low Conduction when molten or in water non-conductors (polar ones ionise in water) Solvent water organic solvents Worked example
Carbon tetrachloride is a liquid that does not conduct electricity. Give two reasons from its bonding.
Try it first, then show the solutionSolution
- It is made of separate CCl₄ molecules with weak forces between them, so its boiling point is low: it is a liquid.
- Its bonds are covalent and it has no ions or free electrons, so it cannot carry current.
Answer: Weak intermolecular forces (liquid); no free ions (non-conductor).
- Coordinate bonding: hydronium and ammonium ions
A lone pair is a pair of outer electrons not used in bonding. A coordinate bond is a covalent bond in which both shared electrons come from one atom (the donor); the other atom (the acceptor) needs a pair, like a hydrogen ion H⁺ which has no electrons.
- Hydronium ion: the oxygen of water donates one of its two lone pairs to H⁺: . H₃O⁺ has three O–H bonds and one lone pair left on O.
- Ammonium ion: the nitrogen of ammonia donates its only lone pair to H⁺: . NH₄⁺ has four N–H bonds and no lone pair.
Once formed, the coordinate bond is just like the other bonds; the + charge belongs to the whole ion, so write it outside square brackets. In a dot diagram, the coordinate pair can be shown with an arrow from the donor to H⁺ before bonding.
Worked example
How many lone pairs are there on the central atom in (a) H₂O, (b) H₃O⁺, (c) NH₃, (d) NH₄⁺?
Try it first, then show the solutionSolution
- H₂O: O has 6 outer electrons, uses 2 in bonding, keeps 2 lone pairs.
- H₃O⁺: one lone pair is donated to H⁺, so 1 remains.
- NH₃: N has 5, uses 3, keeps 1 lone pair.
- NH₄⁺: that lone pair is donated, so none remains.
Answer: (a) 2 (b) 1 (c) 1 (d) 0
Chemistry in real life: Chemical Bonding
Each concept, met in an everyday situation. Read the situation, try the problem, then check the solution. The one-line hook is what to remember.
Conductivity of ionic compounds
Suppose a student tests three white substances with a simple circuit and bulb: dry table salt crystals, a solution of table salt in water, and solid sugar dissolved in water.
Predict which of the three lights the bulb, and explain using the type of bonding.
Try it first, then show the solutionSolution
- Table salt (NaCl) is ionic; in the dry crystal the ions are fixed, so the bulb does not glow.
- In water the Na⁺ and Cl⁻ ions are free to move, so the bulb glows.
- Sugar is covalent; its solution contains molecules, not ions, so the bulb does not glow.
Answer: Only the salt solution conducts.
Memory hook: No moving ions, no current.
Coordinate bonding in fertiliser salts
Suppose a farmer reads 'ammonium sulphate' on a fertiliser bag and asks a student why ammonia, a gas, ends up as part of a solid salt.
Explain, using lone pairs, how ammonia becomes the ammonium ion in an acid.
Try it first, then show the solutionSolution
- Nitrogen in NH₃ has one lone pair.
- In an acid there are H⁺ ions, which have no electrons.
- N donates its lone pair to H⁺, forming a coordinate bond: .
- The ammonium ion then forms an ionic salt with the sulphate ion.
Answer: The lone pair on nitrogen bonds to H⁺, giving NH₄⁺, which forms a salt.
Memory hook: Ammonia brings its own pair to the hydrogen ion.
Covalent compounds and low boiling points
Suppose a cook notices that the methane-rich biogas from a village plant stays a gas even on a cold winter night, while common salt kept beside the stove never melts.
Explain the difference using the forces in each substance.
Try it first, then show the solutionSolution
- Methane is covalent: separate CH₄ molecules with weak forces between them.
- Very little energy separates the molecules, so its boiling point is far below room temperature.
- Salt is ionic: strong electrostatic forces in a giant lattice need very high temperatures to break.
Answer: Weak forces between methane molecules; strong forces between ions in salt.
Memory hook: Weak pulls between molecules, strong pulls between ions.
Topics in this chapter
- Covalent Bonding: Polar and Non-polar MoleculesComing soon
- Electrovalent (Ionic) Bonding
- Coordinate Bonding: Hydronium and Ammonium IonsComing soon
- Coordinate Bonding: Hydronium and Ammonium Ions
- Covalent Bonding, Polar and Non-polar Molecules
Chemical Bonding formula sheet
- Formation of the hydronium ion
- Coordinate bond from a lone pair on oxygen.
- Formation of the ammonium ion
- Coordinate bond from the lone pair on nitrogen.
- Ionisation of HCl in water
- A polar covalent compound gives ions in water.
- Dissociation of an ionic compound
- Ions already exist; melting or dissolving frees them.
- Electron transfer in CaO
- Charges equal electrons lost or gained.
Chemical Bonding: diagrams to practise
Practise each one on paper: draw it from the checklist, then tick off every label.
Electron dot structure of sodium chloride
Draw the dot and cross structure of NaCl (or MgCl₂ or CaO).
Draw
- Write Na with one cross (its outer electron) and Cl with seven dots.
- Draw an arrow showing the cross moving from Na to Cl.
- Write the product: [Na]⁺ and [Cl]⁻, with the chloride showing 7 dots + 1 cross, in square brackets with charges at the top right.
Label
- Na⁺
- Cl⁻
- transferred electron
Watch out: For MgCl₂ use two Cl atoms; for CaO move two crosses to the one O atom.
Electron dot structures of H₂O and NH₃
Show the lone pairs on oxygen in water or nitrogen in ammonia.
Draw
- Water: O in the centre with 6 dots; each H with 1 cross; one dot-cross pair between O and each H.
- Show the two remaining pairs of dots on O as lone pairs.
- Ammonia: N in the centre with 5 dots; three H atoms each sharing a dot-cross pair; one pair of dots left on N.
Label
- shared pair
- lone pair
Watch out: Count: every H has 2 electrons around it; O and N have 8.
Formation of the ammonium ion (coordinate bond)
Explain the formation of NH₄⁺ (or H₃O⁺) with an electron dot diagram.
Draw
- Draw NH₃ as above with its lone pair.
- Draw H⁺ with no electrons beside it.
- Draw an arrow from the lone pair of N to H⁺.
- Draw the product: N with four shared pairs to four H atoms, no lone pair, inside square brackets with + outside.
Label
- lone pair (donated)
- coordinate bond
- [NH₄]⁺
Watch out: Do not show both the arrow and a separate lone pair in the product.
How the board asks Chemical Bonding
The question patterns to expect, and the method that works for each.
| Question type | How it is asked | Method |
|---|---|---|
| Draw electron dot (or dot and cross) structures | Section B, 2-3 marks: draw the structure of MgCl₂, CaO, N₂, Cl₂, NH₃, H₂O, CCl₄, NH₄⁺ or H₃O⁺. | Use dots for one atom and crosses for the other; show every lone pair; for ions, use square brackets and the charge. |
| Lone pair MCQs | Section A: the number of lone pairs on O in water, on N in ammonia or in the ammonium ion; which molecule has a triple bond. | Outer electrons minus electrons used in bonds, divided by 2. |
| Compare and give reasons | Why ionic compounds have high melting points, why covalent compounds do not conduct, why CCl₄ is non-polar, why noble gases do not form bonds. | Name the particles (ions or molecules) and the forces between them; for noble gases, say 'stable electronic configuration'. |
| Letter-table questions | Atoms A to D given with configurations; state the type of bond and the formula of the compound between two of them, using the letters. | Metal with non-metal: electrovalent; two non-metals: covalent; criss-cross valencies; keep the letters. |
| Match the columns | Section A, Question 2: match compounds with bond types or properties. | CaO, NaCl, MgCl₂ ionic; H₂O, NH₃, HCl polar covalent; CCl₄, CH₄, N₂ non-polar. |
Tricks to remember Chemical Bonding
Short memory aids. Say each one aloud once, then use it on a question the same day.
Lone pairs: 3-2-1-0
Count across from chlorine: Cl in HCl has 3 lone pairs, O in H₂O has 2, N in NH₃ has 1, C in CH₄ has 0. Each step left loses one lone pair and gains one bond.
Use it when: Lone pair MCQs and dot diagrams.
Give one, lose one
Every coordinate bond to H⁺ uses up one lone pair: H₂O (2) becomes H₃O⁺ (1); NH₃ (1) becomes NH₄⁺ (0).
Use it when: Lone pairs in the ions.
Metal + non-metal = ions
Metal meets non-metal: transfer (ionic). Non-metal meets non-metal: share (covalent).
Use it when: Bond type from a table of letters.
Ions are hard and hot, molecules are soft and cool
Ionic: hard solids, high melting point. Covalent: gases, liquids or soft solids, low melting point.
Use it when: Comparison tables.
Chemical Bonding: board-level solved questions
Ordered from board level to HOTS. Cover the solution, write your own, then compare step by step.
Example 1: Lone pairs in ammonia · 1 mark · MCQBoard level
The number of lone pairs on the nitrogen atom in an ammonium ion is:
(a) 0
(b) 1
(c) 2
(d) 3
Try it first, then show the solutionSolution
- NH₃ has one lone pair on N.
- It is donated to H⁺ to form NH₄⁺, so none is left.
Answer: (a) 0
Example 2: Polarity · 1 mark · Assertion-reasonHarder board level
Assertion (A): Carbon tetrachloride is a non-polar molecule.
Reason (R): Chlorine is more electronegative than carbon.
(a) Both (A) and (R) are true, and (R) is the correct explanation for (A).
(b) Both (A) and (R) are true, but (R) is not the correct explanation for (A).
(c) (A) is true and (R) is false.
(d) (A) is false and (R) is true.
Try it first, then show the solutionSolution
- Both statements are true.
- But (R) alone would make the molecule polar; CCl₄ is non-polar because its four C–Cl bonds are arranged symmetrically and their pulls cancel.
Answer: (b)
Example 3: Dot and cross for CaO · 2 marks · Short answerBoard level
Draw the electron dot structure of calcium oxide. (Ca = 20, O = 8)
Try it first, then show the solutionSolution
- Ca: 2, 8, 8, 2; show its 2 outer electrons as crosses. O: 2, 6; show its 6 outer electrons as dots.
- Draw two arrows: both crosses move from Ca to O.
- Result: [Ca]²⁺ with no outer electrons shown, and [O]²⁻ with 6 dots and 2 crosses (8 in all), in square brackets.
Answer: Ca²⁺ and O²⁻ with an octet of 6 dots + 2 crosses around O, each ion in brackets with its charge.
Example 4: Letter atoms · 3 marks · Short answerHarder board level
Atoms P, Q, R and S have configurations 2, 8, 1; 2, 4; 2, 8, 7; 2, 6. Using the letters only: (a) the compound of P and R and its bond type; (b) the compound of Q and R and its bond type; (c) the element that forms a diatomic molecule with a double bond.
Try it first, then show the solutionSolution
- P is a metal (valency 1), R a non-metal (valency 1): PR, electrovalent.
- Q (valency 4) and R (valency 1) are both non-metals: QR₄, covalent.
- S has 6 outer electrons and needs 2: S₂ shares two pairs, a double bond.
Answer: (a) PR, electrovalent (b) QR₄, covalent (c) S
Example 5: Hydronium ion · 3 marks · Short answerBoard level
Explain with an electron dot diagram the formation of the hydronium ion. How many lone pairs does the ion have?
Try it first, then show the solutionSolution
- Draw H₂O: O with 6 dots, sharing one pair with each H (crosses); two lone pairs remain on O.
- Draw H⁺ with no electrons; an arrow from one lone pair of O to H⁺.
- Product: [H₃O]⁺ with three O–H shared pairs and one lone pair, the + outside the brackets.
Answer: One lone pair remains on oxygen.
Example 6: Reasoning about melting · 2 marks · Short answerHarder board level
Magnesium oxide melts at about 2850 °C, while hydrogen chloride boils at about -85 °C. Explain in terms of bonding and particles.
Try it first, then show the solutionSolution
- MgO is ionic: a lattice of Mg²⁺ and O²⁻ ions held by strong electrostatic forces; doubly charged ions attract even more strongly.
- HCl is covalent: separate molecules with only weak forces between them.
Answer: Strong ionic lattice versus weak intermolecular forces.
Example 7: Water versus ammonia · 3 marks · Short answerHOTS / competency
Water and ammonia both form ions with H⁺. (a) Name the type of bond formed. (b) Which ion still has a lone pair? (c) Why can't methane form a similar ion?
Try it first, then show the solutionSolution
- (a) Coordinate bond.
- (b) H₃O⁺ (water starts with two lone pairs and uses one).
- (c) Carbon in CH₄ has used all four outer electrons in bonds: it has no lone pair to donate.
Answer: (a) Coordinate (b) H₃O⁺ (c) Methane has no lone pair.
Example 8: Unknown compound · 3 marks · Short answerHarder board level
Compound Z is a white crystalline solid with a high melting point. It does not dissolve in kerosene and its aqueous solution conducts electricity. (a) State the type of bonding. (b) Would molten Z conduct? (c) Choose a likely Z from: CCl₄, CaO, CH₄, NH₃.
Try it first, then show the solutionSolution
- Crystalline, high melting, insoluble in organic solvent, conducting solution: electrovalent.
- Molten ionic compounds have mobile ions, so yes.
- Of the options, only CaO is ionic.
Answer: (a) Electrovalent (b) Yes (c) CaO
Case-study practice (Section B style)
Read the situation, then answer every part. In the board paper this is a 6-mark question split into 2 + 2 + 2 marks.
A laboratory sorting exercise
Suppose a teacher gives a class four labelled samples: sodium chloride, carbon tetrachloride, ammonia solution and magnesium chloride, and asks them to sort the compounds and predict their behaviour.
(i) · 2 marks
Which two are electrovalent? State one property they share.
Answer
Answer: Sodium chloride and magnesium chloride; both conduct when molten or dissolved (or: both have high melting points).
(ii) · 2 marks
Which compound is non-polar covalent? Why is it non-polar although its bonds are polar?
Answer
Answer: Carbon tetrachloride; the four bonds are symmetrical, so their pulls cancel.
(iii) · 2 marks
Ammonia solution turns red litmus blue. Show with an equation the coordinate bond that forms the positive ion in it.
Answer
Answer: (the H⁺ comes from water, leaving OH⁻).
Where the marks are
How a typical answer is split into step marks. Show every step: a right final answer alone rarely earns full marks.
Draw the electron dot structure of a nitrogen molecule. (2 marks) (2 marks)
| Step | Marks |
|---|---|
| Three shared pairs between the two N atoms (triple bond), dots for one N and crosses for the other | 1 |
| One lone pair on each N atom | 1 |
Draw the dot and cross structure of magnesium chloride and state two properties it shows because of its bonding. (3 marks) (3 marks)
| Step | Marks |
|---|---|
| Mg loses one electron to each of two Cl atoms (arrows shown) | 1 |
| [Mg]²⁺ and two [Cl]⁻ with octets, charges outside brackets | 1 |
| Any two: high melting point; conducts when molten or in solution; soluble in water | 1 |
Give four differences between electrovalent and covalent compounds. (4 marks) (4 marks)
| Step | Marks |
|---|---|
| Transfer versus sharing of electrons | 1 |
| Ions versus molecules; crystalline solids versus gases/liquids/soft solids | 1 |
| High versus low melting and boiling points | 1 |
| Conduct when molten or aqueous versus non-conductors; soluble in water versus organic solvents | 1 |
Where students lose marks in Chemical Bonding
The slips examiners see most often, and what to write instead.
Mistake: Drawing bond lines with the dots
CISCE examiners' comments, 2024: in electron dot structures, candidates drew lines between dots or between a dot and a cross, used the same symbol for both atoms, and omitted the lone pair on each nitrogen.
Wrong working
N≡N drawn with dots and three lines, no lone pairs.
Right working
Three dot-cross pairs between the N atoms and one lone pair on each N; no lines.
Do this: Dots for one atom, crosses for the other, no lines, and count every outer electron.
Usually costs: 1-2 marks.
Mistake: Leaving out the charges in an ionic structure
CISCE examiners' comments, 2025: in the dot and cross structure of MgCl₂, candidates missed the ionic charges, showed covalent sharing, or did not distinguish Mg and Cl electrons.
Wrong working
Mg shares a pair with each Cl.
Right working
[Mg]²⁺ 2[Cl]⁻, with the two transferred electrons shown as crosses on the chlorides.
Do this: Ionic structures always show transfer arrows, brackets and charges.
Usually costs: 1-2 marks.
Mistake: Wrong lone pairs in water and ammonia
CISCE examiners' comments, 2024: candidates gave water's oxygen one lone pair (confusing it with ammonia) and sometimes gave hydrogen a lone pair.
Wrong working
Oxygen in water has one lone pair.
Right working
Oxygen in water has two lone pairs; nitrogen in ammonia has one; hydrogen has none.
Do this: Use the 3-2-1-0 rule from Cl to C.
Usually costs: 1 mark.
Mistake: Vague reasons for inertness and low melting points
CISCE examiners' comments, 2024: candidates wrote 'they are inert' instead of 'stable electronic configuration', and 'less force' without naming the weak forces between molecules.
Wrong working
Noble gases do not react because they are inert.
Right working
Noble gases have a complete (stable) outer shell, so they have no tendency to lose, gain or share electrons.
Do this: Every reason names the cause: configuration, particles, or forces between them.
Usually costs: 1 mark per reason.
Mistake: Identifying letter elements and wrong formulae
CISCE examiners' comments, 2024: when atoms were given as letters, candidates named the elements (CaO, CCl₄) instead of using letters, or wrote A₂B₂.
Wrong working
A (2, 8, 8, 2) with B (2, 6): CaO
Right working
AB (both valency 2, simplified ratio)
Do this: Use only the letters; criss-cross and simplify.
Usually costs: 1 mark.
Mistake: Calling CCl₄ polar
CISCE examiners' comments, 2024: in a fill-in-the-blank, candidates chose 'polar' for carbon tetrachloride.
Wrong working
CCl₄ is a polar covalent compound.
Right working
CCl₄ is non-polar: its symmetrical shape cancels the pulls of the polar bonds.
Do this: The syllabus lists CCl₄ with the non-polar examples.
Usually costs: 1 mark.
Practice questions on Chemical Bonding
Write each answer on paper first. Open the hint only if you are stuck, and the answer only when you have finished.
Q1 · 1 mark · MCQBoard level
Which molecule contains a triple bond?
(a) O₂
(b) N₂
(c) Cl₂
(d) CH₄Hint
Valency 3.
Answer
(b) N₂
Q2 · 1 mark · MCQBoard level
The compound with the highest melting point is:
(a) CCl₄
(b) NH₃
(c) CaO
(d) HClHint
Ionic lattice.
Answer
(c) CaO
Q3 · 1 mark · MCQHarder board level
An atom X (2, 8, 6) combines with hydrogen. The number of lone pairs on X in the compound is:
(a) 0
(b) 1
(c) 2
(d) 3Hint
Like oxygen in water.
Answer
(c) 2: X forms XH₂ and keeps two lone pairs.
Q4 · 1 mark · Assertion-reasonBoard level
Assertion (A): The ammonium ion has no lone pair of electrons.
Reason (R): The lone pair of nitrogen is used to form a coordinate bond with H⁺.
(a) Both (A) and (R) are true, and (R) is the correct explanation for (A).
(b) Both (A) and (R) are true, but (R) is not the correct explanation for (A).
(c) (A) is true and (R) is false.
(d) (A) is false and (R) is true.Hint
Where does the pair go?
Answer
(a)
Q5 · 2 marks · Short answerBoard level
Draw the electron dot structures of (a) chlorine molecule, (b) methane.
Hint
Count lone pairs.
Answer
(a) Cl–Cl: one shared pair, three lone pairs on each Cl. (b) C in the centre sharing one pair with each of four H atoms; no lone pairs.
Q6 · 3 marks · Short answerHarder board level
Element A (atomic number 19) combines with element B (atomic number 17). (a) State the type of bond. (b) Write the formula. (c) Would the compound conduct electricity in the solid state? Explain.
Hint
A metal and a halogen.
Answer
(a) Electrovalent (b) AB (c) No: ions are fixed in the solid lattice.
Q7 · 3 marks · Short answerHarder board level
Give reasons: (a) Ammonia gas readily dissolves in water. (b) Electrovalent compounds are hard solids. (c) Methane does not conduct electricity.
Hint
Polarity; lattice; no ions.
Answer
(a) Ammonia is a polar covalent molecule, like water. (b) Strong electrostatic forces hold the ions in a lattice. (c) It is covalent with no free ions or electrons.
Q8 · 4 marks · Long answerHarder board level
Explain, with electron dot diagrams, the formation of the hydronium ion and the ammonium ion. State one difference in the number of lone pairs.
Hint
Each uses one lone pair.
Answer
H₂O donates one of its two lone pairs to H⁺: (one lone pair left). NH₃ donates its only lone pair: (no lone pair left). Diagrams as in the draw-and-label checklist.
Q9 · 3 marks · Short answerHOTS / competency
Element M forms the ion M²⁺ with the configuration 2, 8. Element N forms N³⁻ with the configuration 2, 8. (a) Find the atomic numbers. (b) Write the formula of the compound of M and N. (c) Is it likely to be soluble in kerosene?
Hint
Add back lost electrons; remove gained ones.
Answer
(a) M = 12, N = 7. (b) Criss-cross 2 and 3: M₃N₂. (c) No: it is ionic, and ionic compounds are insoluble in organic solvents.
Q10 · 3 marks · Short answerHarder board level
A molecule YZ has a shared pair closer to Z. Another molecule Z₂ has the pair shared equally. (a) Name the bond type in each. (b) Which of Y and Z is more electronegative? (c) Give one example of each from the syllabus.
Hint
Unequal and equal sharing.
Answer
(a) YZ polar covalent; Z₂ non-polar covalent. (b) Z. (c) HCl and Cl₂.
Q11 · 2 marks · Short answerHOTS / competency
A student draws the dot structure of oxygen with one shared pair and three lone pairs on each atom. Find the error, correct it, and state the bond type.
Hint
Count to eight.
Answer
That drawing gives each O atom 7 electrons of its own (1 in the shared pair + 6 in lone pairs), but oxygen has only 6 outer electrons. Oxygen needs 2 more electrons, so each atom shares two of its electrons: two shared pairs (a double bond) and two lone pairs on each O. Bond type: non-polar covalent double bond.
Test your recall
Answer in your head or on paper first, then open the card. Pulling an answer out of memory makes it stick far better than re-reading.
1.Define an electrovalent bond.Show answer
The bond formed by transfer of electrons from one atom to another, giving oppositely charged ions held by electrostatic attraction.
2.Define a covalent bond.Show answer
A bond formed by mutual sharing of one or more electron pairs between two atoms.
3.Define a coordinate bond.Show answer
A covalent bond in which both shared electrons are provided by one atom.
4.What is a lone pair?Show answer
A pair of outer-shell electrons not used in bonding.
5.Lone pairs on O in water?Show answer
Two.
6.Type of bond in N₂?Show answer
Triple covalent bond.
7.Which ion is formed when water accepts H⁺?Show answer
Hydronium ion, H₃O⁺.
8.Why does molten NaCl conduct?Show answer
Its ions are free to move.
9.Name a polar covalent molecule from the syllabus.Show answer
HCl, H₂O or NH₃.
Best order to study it
- Revise configurations of elements 1-20 and the duplet and octet idea.
- Practise dot and cross diagrams for NaCl, MgCl₂ and CaO.
- Practise H₂, Cl₂, O₂, N₂, CH₄, CCl₄, then HCl, H₂O, NH₃, counting lone pairs every time.
- Learn the coordinate bond with H₃O⁺ and NH₄⁺.
- Finish with the property comparison table and give-reason questions.
Quick revision checklist
The night before the exam: can you do each of these without looking?
- Can you draw NaCl, MgCl₂ and CaO with arrows, brackets and charges?
- Can you draw N₂ and O₂ with the right number of shared and lone pairs?
- Do you know which syllabus molecules are polar and which are non-polar?
- Can you explain why CCl₄ is non-polar?
- Can you draw the formation of NH₄⁺ and H₃O⁺?
- Can you write four differences between electrovalent and covalent compounds?
Chemical Bonding: frequently asked questions
Which compounds must I know electron dot structures for in ICSE Class 10 Chemistry?
The 2027 syllabus names NaCl, MgCl₂ and CaO (electrovalent); H₂, Cl₂, O₂, N₂, CCl₄ and CH₄ (non-polar covalent); HCl, NH₃ and H₂O (polar covalent); and the hydronium and ammonium ions (coordinate).
Do I need to show shapes or orbitals?
No orbitals. Show dots and crosses; mention that CH₄ and CCl₄ are symmetrical (tetrahedral) when explaining why they are non-polar.
Is a coordinate bond different from a covalent bond once formed?
Only in where the electrons came from. In NH₄⁺ all four N–H bonds are the same once the ion has formed.
Why does HCl conduct in water if it is covalent?
Being polar, it ionises in water to give H₃O⁺ and Cl⁻ ions, which carry the current.
Based on: CISCE ICSE 2027 Chemistry (Science Paper 2) syllabus; CISCE ICSE 2027 Chemistry (Science Paper 2) specimen question paper and marking scheme; CISCE Analysis of Pupil Performance, ICSE Chemistry (Science Paper 2), 2025; CISCE Analysis of Pupil Performance, ICSE Chemistry (Science Paper 2), 2024