CBSE Class 12 Physics 2026: question 18(a)
Set in the CBSE Class 12 board exam of 2026, paper 55/1/1, section B, question 18(a), for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q18(a) · 2 marks · Very short answerWave Optics
A beam of light consisting of two wavelengths 400 nm and 600 nm is used to illuminate a single slit of width 1 mm. Find the least distance of the point from the central maximum where the dark fringes due to both wavelengths coincide on the screen placed 1.5 m from the slit.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 55/1/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Dark fringes in single-slit diffraction occur where .
Hint 2
Find the smallest whole numbers and with .
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- ½ mark
In single-slit diffraction the th minimum lies at .
- ½ mark
For the minima to coincide: . The least distance corresponds to , .
- 1 mark
m mm
Answer: 1.8 mm from the central maximum
Where the marks are
- Writes the position of a minimum, (½ mark)
- Coincidence condition (½ mark)
- Least distance of 1.8 mm (1 mark)
Revise the chapter
- Chapter: Wave Optics (notes, formulas, where marks are lost and every past question)
- Topic: Single Slit Diffraction
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