CBSE Class 12 Physics sample paper 2026-27: question 24
From the official CBSE sample question paper for 2026-27, section C, question 24, for 3 marks. Try it first; the hints and our step-by-step solution are below.
Q24 · 3 marks · Short answerNuclei
The atomic mass of is 15.99493 u. Calculate the binding energy per nucleon of the oxygen nucleus.
(Given: mass of proton = 1.00727 u, mass of neutron = 1.00866 u, 1 u = 931.5 MeV/)
Source: official sample paper from cbseacademic.nic.in (PDF). See it in the full Sample paper 2026-27.
Hints
Open one hint at a time and try again before the next.
Hint 1
First count protons and neutrons in the nucleus.
Hint 2
Mass defect = (mass of separated nucleons) − (given mass).
Hint 3
Multiply the mass defect in u by 931.5 to get MeV, then divide by 16.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
For O: , . Mass of nucleons: u.
- 1 mark
Mass defect: u.
- 1 mark
Binding energy: MeV. Binding energy per nucleon: MeV.
Answer: ≈ 7.71 MeV per nucleon (B ≈ 123.4 MeV)
Where the marks are
- Total nucleon mass 16.12744 u (1 mark)
- Mass defect 0.13251 u (1 mark)
- B ≈ 123.4 MeV and B/A ≈ 7.71 MeV (1 mark)
Revise the chapter
- Chapter: Nuclei (notes, formulas, where marks are lost and every past question)
- Topic: Mass Defect and Binding Energy
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