Skip to content
PhysicsCBSE Class 12 · Board exam 2025, set 55/1/1 · 3 marks · Short answer

CBSE Class 12 Physics 2025: question 22(a)

Set in the CBSE Class 12 board exam of 2025, paper 55/1/1, section C, question 22(a), for 3 marks. Try it first; the hints and our step-by-step solution are below.

Q22(a) · 3 marks · Short answerCurrent Electricity

Two batteries of emf's 3V & 6V and internal resistances 0.2 Ω & 0.4 Ω are connected in parallel. This combination is connected to a 4 Ω resistor. Find :
(i) the equivalent emf of the combination
(ii) the equivalent internal resistance of the combination
(iii) the current drawn from the combination

Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 55/1/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

For cells in parallel, the equivalent emf is a weighted average: .

Hint 2

The internal resistances combine like resistors in parallel. Then use Ohm's law for the whole circuit.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. (i) For two cells in parallel: .

    ½ mark
  2. V.

    ½ mark
  3. (ii) .

    ½ mark
  4. .

    ½ mark
  5. (iii) .

    ½ mark
  6. A.

    ½ mark

Answer: (i) 4 V; (ii) ≈ 0.133 Ω (2/15 Ω); (iii) ≈ 0.97 A

Where the marks are

  • Formula and value V (1 mark)
  • Formula and value (1 mark)
  • Uses and gets ≈ 0.97 A (1 mark)

Revise the chapter

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.