CBSE Class 12 Physics sample paper 2025-26: question 18
From the official CBSE sample question paper for 2025-26, section B, question 18, for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q18 · 2 marks · Very short answerCompetency-basedCurrent Electricity
The following graph shows the potential difference across the terminals of a cell against its load current.
Find,
(I) the emf of the cell and
(II) the internal resistance of the cell.
Figure in the paper: Graph of potential difference (V, vertical, 0-6) against load current (A, horizontal, 0-12): a straight line falling from 6 V at 0 A to 0 V at 12 A. See it in the official paper.
Source: official sample paper from cbseacademic.nic.in (PDF). See it in the full Sample paper 2025-26.
Hints
Open one hint at a time and try again before the next.
Hint 1
Use the relation .
Hint 2
What is V when no current is drawn?
Hint 3
The magnitude of the slope of the V–I graph equals r.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
(I) The terminal voltage is . When the load current , . From the graph, V at , so emf V.
- 1 mark
(II) The slope of the – line is : slope . Hence internal resistance . (Check: at , A.)
Answer: (I) emf = 6 V; (II) r = 0.5 Ω
Where the marks are
- Reads emf as 6 V from the intercept at zero current, with reason (1 mark)
- Finds internal resistance from the slope, (1 mark)
Revise the chapter
- Chapter: Current Electricity (notes, formulas, where marks are lost and every past question)
- Topic: EMF, Internal Resistance and Cells
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