CBSE Class 12 Physics 2024: question 3
Set in the CBSE Class 12 board exam of 2024, paper 55/1/1, section A, question 3, for 1 mark. Try it first; the hints and our step-by-step solution are below.
Q3 · 1 mark · MCQCurrent Electricity
Consider the circuit shown in the figure. The potential difference between points A and B is :
- (A)6 V
- (B)8 V
- (C)9 V
- (D)12 V
Figure in the paper: Two parallel branches between terminals A (left) and B (right). Upper branch: 12 V cell in series with 1 Ω resistor. Lower branch: 6 V cell in series with 0.5 Ω resistor. See it in the official paper.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2024 board paper, set 55/1/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
The two cells, each with its resistor, act as cells connected in parallel.
Hint 2
Use .
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
The two cells are in parallel, so the potential difference between A and B is .
- 1 mark
Substituting: V. Option (B).
Answer: 8 V, option (B)
Where the marks are
- Applies the parallel-cells formula to get 8 V (1 mark)
Revise the chapter
- Chapter: Current Electricity (notes, formulas, where marks are lost and every past question)
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.