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PhysicsCBSE Class 12 · Board exam 2024, set 55/1/1 · 1 mark · MCQ

CBSE Class 12 Physics 2024: question 3

Set in the CBSE Class 12 board exam of 2024, paper 55/1/1, section A, question 3, for 1 mark. Try it first; the hints and our step-by-step solution are below.

Q3 · 1 mark · MCQCurrent Electricity

Consider the circuit shown in the figure. The potential difference between points A and B is :

  1. (A)6 V
  2. (B)8 V
  3. (C)9 V
  4. (D)12 V

Figure in the paper: Two parallel branches between terminals A (left) and B (right). Upper branch: 12 V cell in series with 1 Ω resistor. Lower branch: 6 V cell in series with 0.5 Ω resistor. See it in the official paper.

Source: official question paper from cbse.gov.in (PDF). See it in the full 2024 board paper, set 55/1/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

The two cells, each with its resistor, act as cells connected in parallel.

Hint 2

Use .

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. The two cells are in parallel, so the potential difference between A and B is .

  2. Substituting: V. Option (B).

    1 mark

Answer: 8 V, option (B)

Where the marks are

  • Applies the parallel-cells formula to get 8 V (1 mark)

Revise the chapter

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.