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PhysicsCBSE Class 12 · Board exam 2024, set 55/1/1 · 2 marks · Very short answer

CBSE Class 12 Physics 2024: question 19

Set in the CBSE Class 12 board exam of 2024, paper 55/1/1, section B, question 19, for 2 marks. Try it first; the hints and our step-by-step solution are below.

Q19 · 2 marks · Very short answerRay Optics and Optical Instruments

An object is placed 30 cm in front of a concave mirror of radius of curvature 40 cm. Find the (i) position of the image formed and (ii) magnification of the image.

Source: official question paper from cbse.gov.in (PDF). See it in the full 2024 board paper, set 55/1/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

First find the focal length from the radius of curvature.

Hint 2

Use with the Cartesian signs for a concave mirror.

Hint 3

For a mirror, magnification is .

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. (i) By the sign convention, cm and cm. Mirror formula: gives .

    ½ mark
  2. , so cm. The image is real and lies 60 cm in front of the mirror.

    ½ mark
  3. (ii) Magnification: .

    ½ mark
  4. . The image is inverted and twice the size of the object.

    ½ mark

Answer: (i) v = −60 cm (real, 60 cm in front of mirror); (ii) m = −2

Where the marks are

  • Uses the mirror formula with cm, cm (½ mark)
  • Obtains v = −60 cm (½ mark)
  • Writes (½ mark)
  • Obtains m = −2 (½ mark)

Revise the chapter

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.