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In a series LCR… (Class 12 Physics SQP 2024-25, Q6)

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PhysicsCBSE Class 12 · Sample paper, session 2024-25 · 1 mark · MCQ

CBSE Class 12 Physics sample paper 2024-25: question 6

From the official CBSE sample question paper for 2024-25, section A, question 6, for 1 mark. Try it first; the hints and our step-by-step solution are below.

Q6 · 1 mark · MCQAlternating Current

In a series LCR circuit, the voltage across the resistance, capacitance and inductance is 10 V each. If the capacitance is short circuited the voltage across the inductance will be

  1. (A)10 V
  2. (B) V
  3. (C) V
  4. (D)20 V

Source: official sample paper from cbseacademic.nic.in (PDF). See it in the full Sample paper 2024-25.

Hints

Open one hint at a time and try again before the next.

Hint 1

What do equal voltages tell you about R, and ?

Hint 2

Find the source voltage first, then the new impedance.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. Equal voltages mean . The circuit is at resonance, so the source voltage is V.

    ½ mark

  2. With C shorted, , so . Then V. The answer is (C).

    ½ mark

Answer: V, option (C)

Where the marks are

  • and source voltage 10 V (0.5 mark)
  • , V (0.5 mark)

Revise the chapter

Practise this chapterBoard-style questions from Alternating Current, one at a time, marked against the answer key and marking points.Back to the full paperSample paper 2024-25: every question, by section.

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.