CBSE Class 12 Mathematics 2026: question 37
Set in the CBSE Class 12 board exam of 2026, paper 65/5/1, section E, question 37, for 4 marks. Try it first; the hints and our step-by-step solution are below.
Q37 · 4 marks · Case-basedCompetency-basedProbability
There are three types of vaccines A, A, A, available in the market to protect the population of the country from spread of certain infection. According to a survey conducted, it was found that 25% of the population was given Vaccine A, 35% of the population was given Vaccine A and 40% of the population was given Vaccine A. The survey also stated that the probabilities that Vaccines A, A and A would protect against the infection were 60%, 55% and 50% respectively.
Based on the above information, answer the following questions :
Find the probability that :
- (i)1 mark
The person taking vaccine A will get infected.
- (ii)1 mark
If a person is chosen randomly, he/she will be protected from the infection.
- (iii)(a)2 marks
The person was given Vaccine A, given that the randomly chosen person is infected.
OR
(iii)(b)2 marksThe person was given Vaccine A, given that the randomly chosen person is not infected.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 65/5/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
If a vaccine protects with probability 55%, what is the probability of infection with it?
Hint 2
For a randomly chosen person, add P(vaccine) × P(protected | vaccine) over all three vaccines.
Hint 3
For (iii), use Bayes' theorem: the required term divided by the total probability of being infected (or not infected).
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
Let be the events that a person was given . Let I be the event that the person is infected.
Then , , and , , .
Hence , , .
- 1 mark
(i) (i.e. 45%).
- ½ mark
(ii) By the total probability theorem:
- ½ mark
(ii) .
- 1½ marks
(iii)(a) .
By Bayes' theorem: .
- ½ mark
(iii)(a) .
- 1½ marks
(iii)(b) By Bayes' theorem: .
- ½ mark
(iii)(b) .
Answer: (i) 0.45; (ii) 0.5425; (iii)(a) ; (iii)(b)
Where the marks are
- (i) Probability of infection with is 0.45 (1 mark)
- (ii) Writes the total probability expression for protection (½ mark)
- (ii) Evaluates it as 0.5425 (½ mark)
- (iii)(a) Correct Bayes' theorem expression for (1½ marks)
- (iii)(a) Simplifies to (½ mark)
- (iii)(b) Correct Bayes' theorem expression for (1½ marks)
- (iii)(b) Simplifies to (½ mark)
Revise the chapter
- Chapter: Probability (notes, formulas, where marks are lost and every past question)
- Topic: Bayes' Theorem
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