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MathsCBSE Class 12 · Board exam 2026, set 65/5/1 · 3 marks · Short answer

CBSE Class 12 Mathematics 2026: question 29

Set in the CBSE Class 12 board exam of 2026, paper 65/5/1, section C, question 29, for 3 marks. Try it first; the hints and our step-by-step solution are below.

Q29 · 3 marks · Short answerLinear Programming

Solve the following Linear Programming Problem graphically :

Maximize

subject to constraints

.

Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 65/5/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

Plot each constraint line using its intercepts, then shade the side containing the origin.

Hint 2

Find the intersection of and by subtracting the equations.

Hint 3

Evaluate at every corner of the bounded region.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. Draw the lines (through and ) and (through and ). The lines meet where , .

    The feasible region is bounded and lies in the first quadrant, below both lines (towards the origin). It is shaded with vertices , , and .

    1½ marks
  2. Evaluate at the corner points:

    Corner point
    0
    200
    80 + 180 = 260
    240
    1 mark
  3. Maximum at , .

    ½ mark

Answer: at

Where the marks are

  • Correct lines and shaded feasible region with its corner points (1½ marks)
  • Correct values of Z at all corner points (1 mark)
  • Maximum 260 at (200, 600) (½ mark)

Revise the chapter

  • Chapter: Linear Programming (notes, formulas, where marks are lost and every past question)

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.