CBSE Class 12 Mathematics 2026: question 29
Set in the CBSE Class 12 board exam of 2026, paper 65/5/1, section C, question 29, for 3 marks. Try it first; the hints and our step-by-step solution are below.
Q29 · 3 marks · Short answerLinear Programming
Solve the following Linear Programming Problem graphically :
Maximize
subject to constraints
.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 65/5/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Plot each constraint line using its intercepts, then shade the side containing the origin.
Hint 2
Find the intersection of and by subtracting the equations.
Hint 3
Evaluate at every corner of the bounded region.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1½ marks
Draw the lines (through and ) and (through and ). The lines meet where , .
The feasible region is bounded and lies in the first quadrant, below both lines (towards the origin). It is shaded with vertices , , and .
- 1 mark
Evaluate at the corner points:
Corner point 0 200 80 + 180 = 260 240 - ½ mark
Maximum at , .
Answer: at
Where the marks are
- Correct lines and shaded feasible region with its corner points (1½ marks)
- Correct values of Z at all corner points (1 mark)
- Maximum 260 at (200, 600) (½ mark)
Revise the chapter
- Chapter: Linear Programming (notes, formulas, where marks are lost and every past question)
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.