CBSE Class 12 Mathematics 2026: question 26
Set in the CBSE Class 12 board exam of 2026, paper 65/5/1, section C, question 26, for 3 marks. Try it first; the hints and our step-by-step solution are below.
Q26 · 3 marks · Short answerCompetency-basedDifferential Equations
A spherical balloon loses its volume due to escape of air from it in such a way that decrease of volume at any instant is proportional to its surface area. Show that the radius is decreasing at a constant rate.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 65/5/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Translate 'rate of decrease of volume is proportional to surface area' into an equation with a constant .
Hint 2
Differentiate with respect to time and compare the two expressions for .
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
Let be the radius and the volume at time . The volume decreases at a rate proportional to the surface area, so , where is a constant.
- 1 mark
Differentiating with respect to : . Hence .
- 1 mark
Therefore , which is a negative constant. So the radius decreases at a constant rate.
Answer: (a constant), so the radius decreases at a constant rate
Where the marks are
- Forms with (1 mark)
- Uses and equates the two (1 mark)
- Gets and concludes (1 mark)
Revise the chapter
- Chapter: Differential Equations (notes, formulas, where marks are lost and every past question)
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