CBSE Class 12 Mathematics 2025: question 30
Set in the CBSE Class 12 board exam of 2025, paper 65/7/1, section C, question 30, for 3 marks. Try it first; the hints and our step-by-step solution are below.
Q30 · 3 marks · Short answerLinear Programming
In the Linear Programming Problem for objective function subject to constraints
find the minimum value of Z.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 65/7/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
For '≥' constraints, the feasible region lies on the side of each line away from the origin and is unbounded.
Hint 2
Find the intersection of the two lines, evaluate Z at every corner, and remember the extra check needed for an unbounded region.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1½ marks
Graph: passes through and , and passes through and . Both inequalities are '≥', so the region lies away from the origin. With the feasible region is unbounded, lying above both lines in the first quadrant. Solving the two lines: gives , so and . The corner points are , and .
- 1 mark
Corner point A(0, 20) 200 B(3, 8) 134 C(15, 0) 270 - ½ mark
The region is unbounded, so draw the half-plane . It has no point in common with the feasible region. Hence the minimum value of Z is 134 at (3, 8).
Answer: Minimum Z = 134 at (3, 8)
Where the marks are
- Correct graph of the unbounded feasible region with corner points (1½ marks)
- Evaluates Z at A, B, C correctly (1 mark)
- Checks the half-plane and concludes min Z = 134 at (3,8) (½ mark)
Revise the chapter
- Chapter: Linear Programming (notes, formulas, where marks are lost and every past question)
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