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MathsCBSE Class 12 · Board exam 2024, set 65/1/1 · 3 marks · Short answer

CBSE Class 12 Mathematics 2024: question 30

Set in the CBSE Class 12 board exam of 2024, paper 65/1/1, section C, question 30, for 3 marks. Try it first; the hints and our step-by-step solution are below.

Q30 · 3 marks · Short answerLinear Programming

Solve the following linear programming problem graphically :
Maximise ,
subject to constraints



Source: official question paper from cbse.gov.in (PDF). See it in the full 2024 board paper, set 65/1/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

Plot each constraint line using its intercepts and find the side that satisfies the inequality.

Hint 2

Solve and together to get one corner.

Hint 3

Evaluate z at every corner of the bounded region and pick the largest.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. Graph: draw through ; through ; through . The feasible region (in the first quadrant, below both and , above ) is the bounded pentagon with corners , , [intersection of and ], , .

    1½ marks
  2. Values of at corners:

    Corner point
    A(0, 4)1200
    B(0, 6)1800
    C(4, 4)3200
    D(6, 0)3000
    E(5, 0)2500
    1 mark
  3. Maximum at .

    ½ mark

Answer: Max z = 3200 at x = 4, y = 4

Where the marks are

  • Correct graph with shaded feasible region and corner points (1.5 marks)
  • Correct corner-point table of z values (1 mark)
  • States maximum 3200 at (4, 4) (0.5 mark)

Revise the chapter

  • Chapter: Linear Programming (notes, formulas, where marks are lost and every past question)

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.