CBSE Class 12 Mathematics 2024: question 30
Set in the CBSE Class 12 board exam of 2024, paper 65/1/1, section C, question 30, for 3 marks. Try it first; the hints and our step-by-step solution are below.
Q30 · 3 marks · Short answerLinear Programming
Solve the following linear programming problem graphically :
Maximise ,
subject to constraints
Source: official question paper from cbse.gov.in (PDF). See it in the full 2024 board paper, set 65/1/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Plot each constraint line using its intercepts and find the side that satisfies the inequality.
Hint 2
Solve and together to get one corner.
Hint 3
Evaluate z at every corner of the bounded region and pick the largest.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1½ marks
Graph: draw through ; through ; through . The feasible region (in the first quadrant, below both and , above ) is the bounded pentagon with corners , , [intersection of and ], , .
- 1 mark
Values of at corners:
Corner point A(0, 4) 1200 B(0, 6) 1800 C(4, 4) 3200 D(6, 0) 3000 E(5, 0) 2500 - ½ mark
Maximum at .
Answer: Max z = 3200 at x = 4, y = 4
Where the marks are
- Correct graph with shaded feasible region and corner points (1.5 marks)
- Correct corner-point table of z values (1 mark)
- States maximum 3200 at (4, 4) (0.5 mark)
Revise the chapter
- Chapter: Linear Programming (notes, formulas, where marks are lost and every past question)
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.