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ChemistryCBSE Class 12 · Board exam 2026, set 56/5/1 · 3 marks · Short answer

CBSE Class 12 Chemistry 2026: question 24

Set in the CBSE Class 12 board exam of 2026, paper 56/5/1, section C, question 24, for 3 marks. Try it first; the hints and our step-by-step solution are below.

Q24 · 3 marks · Short answerChemical Kinetics

The rate of the chemical reaction doubles when the temperature is raised from 298 K to 308 K. Calculate activation energy () for this reaction assuming that it does not change with temperature.
(Given : R = 8·314 J mol K, log 2 = 0·30)

Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 56/5/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

Doubling of rate means .

Hint 2

Use and solve for .

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. Arrhenius relation: , with .

    1 mark
  2. 1 mark
  3. 1 mark

Answer: kJ mol⁻¹ (52722 J mol⁻¹)

Where the marks are

  • Writes the Arrhenius two-temperature equation with (1 mark)
  • Correct substitution (1 mark)
  • kJ mol⁻¹ with unit (1 mark; ½ deducted if the unit is missing or wrong)

Revise the chapter

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.