CBSE Class 12 Chemistry 2026: question 24
Set in the CBSE Class 12 board exam of 2026, paper 56/5/1, section C, question 24, for 3 marks. Try it first; the hints and our step-by-step solution are below.
Q24 · 3 marks · Short answerChemical Kinetics
The rate of the chemical reaction doubles when the temperature is raised from 298 K to 308 K. Calculate activation energy () for this reaction assuming that it does not change with temperature.
(Given : R = 8·314 J mol K, log 2 = 0·30)
Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 56/5/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Doubling of rate means .
Hint 2
Use and solve for .
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
Arrhenius relation: , with .
- 1 mark
- 1 mark
Answer: kJ mol⁻¹ (52722 J mol⁻¹)
Where the marks are
- Writes the Arrhenius two-temperature equation with (1 mark)
- Correct substitution (1 mark)
- kJ mol⁻¹ with unit (1 mark; ½ deducted if the unit is missing or wrong)
Revise the chapter
- Chapter: Chemical Kinetics (notes, formulas, where marks are lost and every past question)
- Topic: Arrhenius Equation and Activation Energy
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.