CBSE Class 12 Chemistry 2026: question 18
Set in the CBSE Class 12 board exam of 2026, paper 56/1/1, section B, question 18, for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q18 · 2 marks · Very short answerHaloalkanes and Haloarenes
Why are haloarenes less reactive towards nucleophilic substitution reaction ? Give two reasons.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 56/1/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Compare the C–X bond in chlorobenzene with the one in chloroethane.
Hint 2
Can the halogen's lone pair interact with the ring's π-system?
Hint 3
What is the hybridisation of the ring carbon bearing X?
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
Resonance effect: a lone pair on the halogen is delocalised into the benzene ring. The C–X bond therefore gets partial double-bond character, becomes stronger and shorter, and is difficult to break.
- 1 mark
Hybridisation of carbon: the C attached to X is hybridised. With more s-character it is more electronegative, holds the bonding pair more tightly, and the C–X bond is shorter and stronger than in haloalkanes ( C). Other acceptable reasons: the phenyl cation is unstable (so is not possible), and the electron-rich ring repels the incoming nucleophile (so backside attack is hindered).
Answer: (1) Resonance gives the C–X bond partial double-bond character; (2) the carbon holds the C–X bond more tightly (also: phenyl cation unstable, nucleophile repelled by the π-electron cloud).
Where the marks are
- Partial double-bond character of C–X due to resonance (1 mark)
- -hybridised carbon makes the C–X bond shorter and stronger / phenyl cation unstable / repulsion of nucleophile by the electron-rich ring (1 mark)
Revise the chapter
- Chapter: Haloalkanes and Haloarenes (notes, formulas, where marks are lost and every past question)
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