CBSE Class 12 Chemistry sample paper 2026-27: question 24
From the official CBSE sample question paper for 2026-27, section C, question 24, for 3 marks. Try it first; the hints and our step-by-step solution are below.
Q24 · 3 marks · Short answerAldehydes, Ketones and Carboxylic Acids
Identify each name reaction and complete the missing reactant/ product in the given reaction sequence. (3x1)
(I)
(II) Toluene benzal compound benzaldehyde
(III)
Figure in the paper: Part (II) shows toluene (CH3 on benzene ring), then an intermediate benzene ring bearing CH(OCrOHCl2)2, then benzaldehyde (benzene ring with CHO). See it in the official paper.
Source: official sample paper from cbseacademic.nic.in (PDF). See it in the full Sample paper 2026-27.
Hints
Open one hint at a time and try again before the next.
Hint 1
(I) Two aldehyde molecules join to give a β-hydroxy aldehyde.
Hint 2
(II) Which chromium reagent in CS₂ converts a methyl group on benzene to CHO?
Hint 3
(III) Hydrazine condenses with C=O, losing water. What product forms?
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
(I) Aldol condensation (aldol addition). Missing reagent: dilute NaOH. Two molecules of ethanal give 3-hydroxybutanal.
- 1 mark
(II) Etard reaction. Missing reactant: **chromyl chloride, **. It forms the chromium complex, which is hydrolysed to benzaldehyde.
- 1 mark
(III) Wolff–Kishner reduction. Missing intermediate: the **hydrazone, **. Heating it with KOH in ethylene glycol gives and .
Answer: (I) Aldol, dil. NaOH; (II) Etard, ; (III) Wolff–Kishner, (hydrazone)
Where the marks are
- Aldol + dil NaOH (½ + ½ mark)
- Etard + (½ + ½ mark)
- Wolff–Kishner + hydrazone (½ + ½ mark)
Revise the chapter
- Chapter: Aldehydes, Ketones and Carboxylic Acids (notes, formulas, where marks are lost and every past question)
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