CBSE Class 12 Chemistry 2025: question 19(b)
Set in the CBSE Class 12 board exam of 2025, paper 56/7/1, section B, question 19(b), for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q19(b) · 2 marks · Very short answerCoordination Compounds
Answer the following.
- (i)1 mark
Write the formula of the following coordination compound : Pentaamminecarbonatocobalt(III)chloride
- (ii)1 mark
Write the IUPAC name of the linkage isomer of the complex .
Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 56/7/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Carbonate carries a charge of −2; use it to decide how many chloride ions are needed.
Hint 2
The ligand is ambidentate: it can bind through N or through O.
Hint 3
Name the isomer in which the donor atom is O.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
(i) The carbonate ion is a −2 ligand and Co is +3, so the complex ion is . One chloride balances it: .
- 1 mark
(ii) In the given complex, is bonded through N (nitrito-N). Its linkage isomer is , in which the ligand is bonded through O. Its name is Pentaamminenitrito-O-cobalt(III) chloride.
Answer: (i) ; (ii) Pentaamminenitrito-O-cobalt(III) chloride
Where the marks are
- Correct formula (1 mark)
- Correct name of the O-bonded linkage isomer (1 mark)
Revise the chapter
- Chapter: Coordination Compounds (notes, formulas, where marks are lost and every past question)
- Topic: IUPAC Nomenclature of Coordination Compounds
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