CBSE Class 12 Chemistry 2024: question 5
Set in the CBSE Class 12 board exam of 2024, paper 56/1/1, section A, question 5, for 1 mark. Try it first; the hints and our step-by-step solution are below.
Q5 · 1 mark · MCQChemical Kinetics
For the reaction , the differential form equation of the rate law is :
- (A)
- (B)
- (C)
- (D)
Source: official question paper from cbse.gov.in (PDF). See it in the full 2024 board paper, set 56/1/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Divide each rate of change by its stoichiometric coefficient.
Hint 2
Reactants carry a minus sign and products a plus sign.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
For X + 2Y → P: Rate .
- 1 mark
Multiplying the Y and P terms by 2 gives , which is option (A).
Answer: Option (A)
Where the marks are
- Writes the rate expression with correct stoichiometric factors (1 mark)
Revise the chapter
- Chapter: Chemical Kinetics (notes, formulas, where marks are lost and every past question)
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.