CBSE Class 12 Chemistry 2024: question 24
Set in the CBSE Class 12 board exam of 2024, paper 56/1/1, section C, question 24, for 3 marks. Try it first; the hints and our step-by-step solution are below.
Q24 · 3 marks · Short answerCoordination Compounds
Answer the following.
- (a)1 mark
Write the formula for the following coordination compound : Potassium tetrahydroxidozincate (II)
- (b)1 mark
Arrange the following complexes in the increasing order of conductivity of their solution : , ,
- (c)1 mark
Identify the type of isomerism exhibited by the following complexes : (i) (ii)
Source: official question paper from cbse.gov.in (PDF). See it in the full 2024 board paper, set 56/1/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Only the ions outside the square bracket are released in solution.
Hint 2
NO₂⁻ can bind through two different atoms; en is a bidentate chelating ligand.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
(a) — four OH⁻ ligands on Zn²⁺ give a −2 complex ion, balanced by two K⁺.
- 1 mark
(b) Conductivity depends on the number of ions produced: (0 ions) < (3 ions) < (4 ions).
- 1 mark
(c)(i) : linkage isomerism (ambidentate NO₂⁻ binds through N or O as –ONO). (ii) : optical isomerism (non-superimposable mirror images, d and l forms).
Answer: (a) K₂[Zn(OH)₄]; (b) [Cr(NH₃)₃Cl₃] < [Cr(NH₃)₅Cl]Cl₂ < [Cr(NH₃)₆]Cl₃; (c) (i) linkage, (ii) optical
Where the marks are
- Correct formula K₂[Zn(OH)₄] (1 mark)
- Correct increasing order of conductivity (1 mark)
- Linkage isomerism (½ mark) and optical isomerism (½ mark)
Revise the chapter
- Chapter: Coordination Compounds (notes, formulas, where marks are lost and every past question)
- Topic: Isomerism in Coordination Compounds
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