CBSE Class 12 Chemistry sample paper 2024-25: question 4
From the official CBSE sample question paper for 2024-25, section A, question 4, for 1 mark. Try it first; the hints and our step-by-step solution are below.
Q4 · 1 mark · MCQCompetency-basedHaloalkanes and Haloarenes
Study the graph showing the boiling points of bromoalkanes and identify the compounds.
- (A)1 = Bromomethane, 2= 2-Bromobutane, 3= 1-Bromobutane, 4= 2-Bromo-2-methylpropane
- (B)1 =1-Bromobutane, 2= 2-Bromo-2-methylpropane, 3= 2-Bromobutane, 4= Bromomethane
- (C)1 = Bromomethane, 2=1-Bromobutane, 3= 2-Bromo-2-methylpropane, 4= 2-Bromobutane,
- (D)1 =Bromomethane, 2= 2-Bromo-2-methylpropane, 3=2- Bromobutane, 4= 1-Bromobutane
Figure in the paper: Bar chart titled 'Boiling points of bromoalkanes'. X-axis: Bromoalkanes 1, 2, 3, 4; y-axis: Boiling point/K (0 to 400). Bar values: 1 = 277, 2 = 346, 3 = 364, 4 = 375. See it in the official paper.
Source: official sample paper from cbseacademic.nic.in (PDF). See it in the full Sample paper 2024-25.
Hints
Open one hint at a time and try again before the next.
Hint 1
Smaller molecules boil lower.
Hint 2
For isomers, more branching means a lower boiling point.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
Bromomethane has the smallest molar mass, so it has the lowest b.p. (277 K).
- 1 mark
Among the isomeric bromobutanes, b.p. falls as branching increases because surface area and van der Waals forces decrease. So 1-bromobutane (375 K) > 2-bromobutane (364 K) > 2-bromo-2-methylpropane (346 K). Option (D).
Answer: Option (D)
Where the marks are
- Applies the molar mass and branching trends correctly (1 mark)
Revise the chapter
- Chapter: Haloalkanes and Haloarenes (notes, formulas, where marks are lost and every past question)
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