CBSE Class 10 Science 2026: question 6
Set in the CBSE Class 10 board exam of 2026, paper 31/4/1, section A, question 6, for 1 mark. Try it first; the hints and our step-by-step solution are below.
Q6 · 1 mark · MCQHeredity
Two pea plants, one with round green seeds (RRyy) and another with wrinkled yellow (rrYY) seeds were crossed with each other which produced progeny that have only round yellow (RrYy) seeds. When plants are self-pollinated, the progeny will have which new combination of characters, as compared to the parents:
(i) Round, yellow
(ii) Round, green
(iii) Wrinkled, yellow
(iv) Wrinkled, green
Correct options are:
- (A)(i) and (ii)
- (B)(i) and (iv)
- (C)(ii) and (iv)
- (D)(i) and (iii)
Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 31/4/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
List the parents' phenotypes first.
Hint 2
New combinations are those found in neither parent.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
The parents were round green and wrinkled yellow.
- 1 mark
Because the two traits sort independently, also shows round yellow and wrinkled green. These are the new combinations not seen in either parent. Answer: option (B).
Answer: (B) (i) and (iv)
Where the marks are
- Identifies round yellow and wrinkled green as new combinations, option (B) (1 mark)
Revise the chapter
- Chapter: Heredity (notes, formulas, where marks are lost and every past question)
- Topic: Dihybrid Cross and Laws of Inheritance
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