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Study the given diagram and… (Class 10 Science 2026, Q35)

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ScienceCBSE Class 10 · Board exam 2026, set 31/3/1 · 3 marks · Short answer

CBSE Class 10 Science 2026: question 35

Set in the CBSE Class 10 board exam of 2026, paper 31/3/1, section C, question 35, for 3 marks. Try it first; the hints and our step-by-step solution are below.

Q35 · 3 marks · Short answerCompetency-basedThe Human Eye and the Colourful World

Study the given diagram and answer the questions that follow :

  1. (a)

    Write the name of the eye defect shown in the diagram. Where is the image formed in this eye defect with respect to the retina of the eye ?

    0 marks
  2. (b)

    List two causes of this eye defect.

    0 marks
  3. (c)

    With the help of a diagram, show how this eye defect of vision is corrected.

    0 marks

Figure in the paper: Eye with a lens; points N (far) and N′ (near point) on the left on the principal axis. Rays from N′ pass through the eye lens and converge at a point on the axis at the far right, shown beyond/at the back of the eye. See it in the official paper.

Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 31/3/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

Look at where the rays from the near point N′ meet compared with the retina.

Hint 2

If nearby objects are not seen clearly, which type of lens adds converging power?

Hint 3

For the diagram, the corrective lens should make rays from N appear to come from N′.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. (a) Light from the near point N′ converges at a point beyond the retina, so the defect is hypermetropia (far-sightedness).

    ½ mark

  2. (a) In hypermetropia the image of a nearby object is formed behind the retina.

    ½ mark

  3. (b) Cause 1: the focal length of the eye lens is too long, i.e. the lens has too little converging power.

    ½ mark

  4. (b) Cause 2: the eyeball has become too small, i.e. the distance from the lens to the retina is too short.

    ½ mark

  5. (c) Correction with a convex (converging) lens of suitable power.
    Diagram (described): place a convex lens in front of the eye. Rays from an object at N (the normal near point, 25 cm) pass through the convex lens. They emerge less divergent, as if coming from the hypermetropic near point N′. The eye lens then focuses them exactly on the retina.
    Label: N, N′, convex lens, eye lens, retina, image on retina.

    1 mark

Answer: (a) Hypermetropia; image formed behind the retina. (b) Focal length of eye lens too long; eyeball too small. (c) Corrected by a convex lens that makes rays from N appear to come from N′, so the image forms on the retina.

Where the marks are

  • Names the defect as hypermetropia (½ mark)
  • States that the image forms behind the retina (½ mark)
  • Cause: focal length of eye lens too long (½ mark)
  • Cause: eyeball too small (½ mark)
  • Correct diagram of correction using a convex lens, with the image on the retina (1 mark)

Revise the chapter

Practise this chapterBoard-style questions from The Human Eye and the Colourful World, one at a time, marked against the answer key and marking points.Back to the full paper2026 board paper, set 31/3/1: every question, by section.

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.