CBSE Class 10 Science 2026: question 27(b)
Set in the CBSE Class 10 board exam of 2026, paper 31/3/1, section B, question 27(b), for 3 marks. Try it first; the hints and our step-by-step solution are below.
Q27(b) · 3 marks · Short answerAcids, Bases and Salts
Write the preparation of the following compounds with balanced chemical equation :
- (i)1 mark
NaOH by chlor-alkali process
- (ii)1 mark
Baking Soda
- (iii)1 mark
Plaster of Paris
Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 31/3/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Chlor-alkali means passing electricity through brine. Which three products form?
Hint 2
Baking soda needs ammonia and CO₂ with brine. Plaster of Paris is gypsum that has lost part of its water on heating.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
(i) Chlor-alkali process: electricity is passed through an aqueous solution of NaCl (brine). gas forms at the anode, gas at the cathode, and NaOH solution near the cathode:
- 1 mark
(ii) Baking soda is made from sodium chloride, water, ammonia and carbon dioxide:
- 1 mark
(iii) Plaster of Paris is made by heating gypsum at 373 K:
Answer: (i) 2NaCl + 2H₂O → 2NaOH + Cl₂ + H₂ (electrolysis); (ii) NaCl + H₂O + CO₂ + NH₃ → NH₄Cl + NaHCO₃; (iii) CaSO₄·2H₂O → CaSO₄·½H₂O + 1½H₂O at 373 K.
Where the marks are
- Balanced chlor-alkali equation (1 mark)
- Balanced equation for baking soda (1 mark)
- Balanced equation for Plaster of Paris at 373 K (1 mark); ½ deducted in each case if unbalanced
Revise the chapter
- Chapter: Acids, Bases and Salts (notes, formulas, where marks are lost and every past question)
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