CBSE Class 10 Science 2025: question 31
Set in the CBSE Class 10 board exam of 2025, paper 31/6/1, section C, question 31, for 3 marks. Try it first; the hints and our step-by-step solution are below.
Q31 · 3 marks · Short answerCompetency-basedLight – Reflection and Refraction
A student placed a candle flame at different distances from a convex lens and focused its image on a screen. He recorded his observation in tabular form as given below :
| S.No. | Distance of flame from the lens (cm) | Distance of the image from the lens |
|---|---|---|
| 1 | −90 | +18 |
| 2 | −60 | +20 |
| 3 | −40 | +24 |
| 4 | −30 | +30 |
| 5 | −24 | +40 |
| 6 | −20 | +60 |
| 7 | −18 | +90 |
| 8 | −12 | +120 |
Analyse the observation table and on the basis of your analysis only, answer the following questions (without doing any calculations) :
- (a)0 marks
What is the focal length of the convex lens used ? Give reason to justify your answer.
- (b)0 marks
Which one of the sets of observations is not correct and why ?
- (c)0 marks
Draw ray diagram to show image formation for any correct set of observation.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 31/6/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Look for the row where object and image distances are equal. Where must the object be for that to happen?
Hint 2
Once you know f, check which object distance is less than f. What kind of image does a convex lens form then?
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- ½ mark
(a) Focal length cm.
- ½ mark
(a) Reason: in observation 4, object distance = image distance = 30 cm. This happens only when the object is at and the image is at . So cm, giving cm.
- ½ mark
(b) Observation No. 8 ( cm, cm) is not correct.
- ½ mark
(b) Reason: 12 cm is less than cm, so the object is between the optical centre and the focus. A convex lens then forms a virtual, erect image on the same side as the object, which cannot be caught on a screen. So cannot be cm; it should be negative.
- 1 mark
(c) Ray diagram for observation 4 (object at , 30 cm):
- Draw the convex lens on the principal axis. Mark , on the left and , on the right, 15 cm and 30 cm from O.
- Place an upright object AB at .
- A ray from B parallel to the principal axis refracts through .
- A ray from B through the optical centre O goes on undeviated.
- The rays meet below the axis at B′, forming image A′B′ at .
- The image is real, inverted and the same size as the object. Arrows show the direction of the rays.
Answer: (a) f = +15 cm (u = v = 30 cm means object at 2F); (b) Observation 8, since object within f gives a virtual image on the same side; (c) ray diagram for object at 2F giving a real, inverted, same-size image at 2F′.
Where the marks are
- Focal length 15 cm (½ mark)
- Reason: u = v at 2F, so 2f = 30 cm (½ mark)
- Identifies observation 8 (½ mark)
- Reason: object lies between O and F, so the image is virtual and on the same side (½ mark)
- Correct labelled ray diagram for any correct observation (1 mark)
Revise the chapter
- Chapter: Light – Reflection and Refraction (notes, formulas, where marks are lost and every past question)
More questions from Light – Reflection and Refraction
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.