CBSE Class 10 Science 2025: question 25(a)
Set in the CBSE Class 10 board exam of 2025, paper 31/1/1, section B, question 25(a), for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q25(a) · 2 marks · Very short answerElectricity
A wire of resistance R is cut into three equal parts. If these three parts are then joined in parallel, calculate the total resistance of the combination so formed.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 31/1/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
How does the resistance of a wire depend on its length?
Hint 2
Each piece is one-third as long. What is its resistance?
Hint 3
Add the reciprocals of the three equal resistances.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- ½ mark
Resistance is proportional to length (). Each of the three equal parts therefore has resistance .
- ½ mark
For resistors in parallel:
- ½ mark
Substituting:
- ½ mark
Therefore the total resistance of the combination is .
Answer: R_p = R/9
Where the marks are
- Finds the resistance of each part as (½ mark)
- Writes the parallel-combination formula (½ mark)
- Substitutes correctly (½ mark)
- Gets (½ mark)
Revise the chapter
- Chapter: Electricity (notes, formulas, where marks are lost and every past question)
More questions from Electricity
- 2025 board paper, set 31/1/1, Q25(b) · 2 marksDefine electric power. When do we say that the power consumed in an electric circuit is 1 watt?
- 2025 board paper, set 31/1/1, Q32 · 3 marksConsider the following electric circuit. Calculate the values of the following:
- 2025 board paper, set 31/1/1, Q33 · 3 marksAnswer the following.
The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.