CBSE Class 10 Science sample paper 2024-25: question 32
From the official CBSE sample question paper for 2024-25, section C, question 32, for 3 marks. Try it first; the hints and our step-by-step solution are below.
Q32 · 3 marks · Short answerElectricity
A. State the relationship between the resistance R of a wire to its length l and cross sectional area A. Use the mathematical symbols to arrive at the final formula.
B. Using the formula define the resistivity of a material.
Source: official sample paper from cbseacademic.nic.in (PDF). See it in the full Sample paper 2024-25.
Hints
Open one hint at a time and try again before the next.
Hint 1
How does resistance change if you double the length? If you double the thickness?
Hint 2
Combine the two proportionalities and introduce a constant.
Hint 3
Make ρ the subject and choose unit values for l and A.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- ½ mark
A. The resistance of a wire is directly proportional to its length:
- ½ mark
It is inversely proportional to its area of cross-section: . Combining, .
- ½ mark
So , where is a constant called the resistivity of the material.
- 1 mark
B. Rearranging, . If m and , then .
- ½ mark
Resistivity is the resistance of a wire of the material of length 1 m and cross-sectional area 1 m². Its SI unit is Ω m.
Answer: R = ρl/A; resistivity is the resistance of a 1 m long conductor of the material with 1 m² cross-sectional area (unit Ω m).
Where the marks are
- and (1 mark)
- Final formula (0.5 mark)
- Rearranges to and substitutes l = 1 m, A = 1 m² (1 mark)
- Correct definition of resistivity (0.5 mark)
Revise the chapter
- Chapter: Electricity (notes, formulas, where marks are lost and every past question)
- Topic: Resistance and Resistivity
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