CBSE Class 10 Science 2023: question 21(b)
Set in the CBSE Class 10 board exam of 2023, paper 31/2/1, section B, question 21(b), for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q21(b) · 2 marks · Very short answerChemical Reactions and Equations
When copper powder is heated in a watch glass, a black substance is formed.
- (i)1 mark
Why is this black substance formed ? Name it.
- (ii)1 mark
How can this black substance be reversed to its original form ?
Source: official question paper from cbse.gov.in (PDF). See it in the full 2023 board paper, set 31/2/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Heating is done in open air. Which gas in air can combine with copper?
Hint 2
To get copper back, oxygen must be removed. Which gas is a common reducing agent?
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- ½ mark
(i) When copper is heated in air, it combines with oxygen, so copper is oxidised:
- ½ mark
(i) The black substance is copper(II) oxide, .
- 1 mark
(ii) Pass hydrogen gas over the heated black copper oxide. It is reduced back to brown copper:
Answer: (i) Copper is oxidised by oxygen of air; black substance is copper oxide (CuO). (ii) By passing hydrogen gas over heated CuO: CuO + H₂ → Cu + H₂O
Where the marks are
- Reason: copper combines with oxygen, i.e. it is oxidised (½ mark)
- Names the substance as copper oxide, CuO (½ mark)
- Reverses it by passing hydrogen over heated CuO, with or without the equation (1 mark)
Revise the chapter
- Chapter: Chemical Reactions and Equations (notes, formulas, where marks are lost and every past question)
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