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MathsCBSE Class 10 · Basic · Board exam 2026, set 430/4/1 · 2 marks · Very short answer

CBSE Class 10 Mathematics Basic 2026: question 25

Set in the CBSE Class 10 board exam of 2026, paper 430/4/1, section B, question 25, for 2 marks. Try it first; the hints and our step-by-step solution are below.

Q25 · 2 marks · Very short answerTriangles

In the given figure, and . If cm, cm, cm and cm, then find the lengths of AR and QC.

Figure in the paper: Triangle ABC with apex A; R lies on AB, Q lies on AC, P lies on BC; QR is parallel to CB (horizontal); RP is parallel to AC. Given BR = 10 cm, QA = 12 cm, BP = 12 cm, PC = 18 cm. See it in the official paper.

Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 430/4/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

Use the Basic Proportionality Theorem twice, once for each pair of parallel lines.

Hint 2

With RP ∥ AC, the sides BA and BC are divided in the same ratio.

Hint 3

Find AR first; then use it with QR ∥ CB to find QC.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. In , , so by BPT: cm

    1 mark
  2. In , , so by BPT: cm

    1 mark

Answer: AR = 15 cm, QC = 8 cm

Where the marks are

  • Applies BPT with to get cm (1 mark)
  • Applies BPT with to get cm (1 mark)

Revise the chapter

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.