If θ = 1/7, then θ is : (A) (1)/(4√(3)) (B) (1)/(2√(3)) (C) (4√(3))/(7) (D) 6/7

MathsCBSE Class 10 · Basic · Board exam 2026, set 430/4/1 · 1 mark · MCQ

CBSE Class 10 Mathematics Basic 2026: question 16

Set in the CBSE Class 10 board exam of 2026, paper 430/4/1, section A, question 16, for 1 mark. Try it first; the hints and our step-by-step solution are below.

Q16 · 1 mark · MCQIntroduction to Trigonometry

If $sin θ = \frac{1}{7}$ , then $tan θ$ is :

(A) $\frac{1}{4 3}$
(B) $\frac{1}{2 3}$
(C) $\frac{4 3}{7}$
(D) $\frac{6}{7}$

Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 430/4/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

Use $sin^{2} θ + cos^{2} θ = 1$ .

Hint 2

$tan θ = \frac{s i n θ}{c o s θ}$ .

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

$cos θ = 1 - \frac{1}{49} = \frac{48}{7} = \frac{4 3}{7}$ .
$tan θ = \frac{sin θ}{cos θ} = \frac{1}{4 3}$ , so option (A).
1 mark

Answer: $\frac{1}{4 3}$ , option (A)

Where the marks are

Finds $cos θ$ and then $tan θ$ (1 mark)

Revise the chapter

Chapter: Introduction to Trigonometry (notes, formulas, where marks are lost and every past question)
Topic: Relationships Between Trigonometric Ratios

Practise this chapterBoard-style questions from Introduction to Trigonometry, one at a time, marked against the answer key and marking points.Back to the full paper2026 board paper, set 430/4/1 (Basic): every question, by section.

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.

CBSE Class 10 Mathematics Basic 2026: question 16

Hints

Step-by-step solution

Revise the chapter

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