CBSE Class 10 Mathematics Basic 2026: question 25

Hints

Open one hint at a time and try again before the next.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

1. Area of quadrant $OPRQ=\frac{1}{4}\pi r^2=\frac{1}{4}\times 3.14\times 10\times 10=78.5{\text{cm}}^2$.

   ½ mark

2. $\angle POS=90^{\circ }$, so area of $△OPS=\frac{1}{2}\times OP\times OS=\frac{1}{2}\times 10\times 6=30{\text{cm}}^2$.

   ½ mark

3. Area of shaded region $=$ area of quadrant $-$ area of $△OPS=78.5-30=48.5{\text{cm}}^2$.

   1 mark

Answer: $48.5{\text{cm}}^2$

Revise the chapter

• Chapter: Areas Related to Circles (notes, formulas, where marks are lost and every past question)
• Topic: Area of a Sector of a Circle