CBSE Class 10 Mathematics Basic 2026: question 28(b)
Set in the CBSE Class 10 board exam of 2026, paper 430/2/1, section C, question 28(b), for 3 marks. Try it first; the hints and our step-by-step solution are below.
Q28(b) · 3 marks · Short answerCompetency-basedPair of Linear Equations in Two Variables
An academy offering cricket coaching bought 10 bats and 5 balls for ₹ 32,500. Later, the academy bought 2 bats and 8 balls for ₹ 10,000. If there is no change in the cost of the bat and of the ball, find the cost of 1 bat and 1 ball.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 430/2/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Let the cost of a bat be and the cost of a ball be , and write one equation for each purchase.
Hint 2
Divide the first equation by 5 to make it simpler.
Hint 3
Subtract one equation from the other so that is eliminated.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
Let the cost of 1 bat be ₹ and the cost of 1 ball be ₹. Then , i.e. ...(1), and ...(2).
- 1 mark
Subtracting (1) from (2): .
- 1 mark
Substituting in (1): . So one bat costs ₹3000 and one ball costs ₹500.
Answer: Cost of 1 bat = ₹3000; cost of 1 ball = ₹500
Where the marks are
- Forms the two linear equations correctly (1 mark)
- Solves to get (1 mark)
- Gets and states both costs (1 mark)
Revise the chapter
- Chapter: Pair of Linear Equations in Two Variables (notes, formulas, where marks are lost and every past question)
- Topic: Word Problems on Linear Equations
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