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MathsCBSE Class 10 · Basic · Board exam 2026, set 430/2/1 · 3 marks · Short answer

CBSE Class 10 Mathematics Basic 2026: question 28(b)

Set in the CBSE Class 10 board exam of 2026, paper 430/2/1, section C, question 28(b), for 3 marks. Try it first; the hints and our step-by-step solution are below.

Q28(b) · 3 marks · Short answerCompetency-basedPair of Linear Equations in Two Variables

An academy offering cricket coaching bought 10 bats and 5 balls for ₹ 32,500. Later, the academy bought 2 bats and 8 balls for ₹ 10,000. If there is no change in the cost of the bat and of the ball, find the cost of 1 bat and 1 ball.

Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 430/2/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

Let the cost of a bat be and the cost of a ball be , and write one equation for each purchase.

Hint 2

Divide the first equation by 5 to make it simpler.

Hint 3

Subtract one equation from the other so that is eliminated.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. Let the cost of 1 bat be ₹ and the cost of 1 ball be ₹. Then , i.e. ...(1), and ...(2).

    1 mark
  2. Subtracting (1) from (2): .

    1 mark
  3. Substituting in (1): . So one bat costs ₹3000 and one ball costs ₹500.

    1 mark

Answer: Cost of 1 bat = ₹3000; cost of 1 ball = ₹500

Where the marks are

  • Forms the two linear equations correctly (1 mark)
  • Solves to get (1 mark)
  • Gets and states both costs (1 mark)

Revise the chapter

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.