CBSE Class 10 Mathematics Basic 2026: question 25
Set in the CBSE Class 10 board exam of 2026, paper 430/1/1, section B, question 25, for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q25 · 2 marks · Very short answerAreas Related to Circles
A chord of a circle of diameter 20 cm subtends an angle of at the centre of the circle. Find the area of the corresponding minor segment of the circle. (Use and )
Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 430/1/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Minor segment = sector − triangle formed by the two radii and the chord.
Hint 2
Radius is half the diameter. Use for the sector.
Hint 3
With a 60° angle between two equal radii, the triangle is equilateral, so its area is .
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- ½ mark
Radius cm, . Area of sector cm².
- 1 mark
The two radii are equal and the included angle is , so the triangle is equilateral with side 10 cm. Area of triangle cm².
- ½ mark
Area of minor segment area of sector area of triangle cm² (approx.).
Answer: Area of minor segment ≈ 9.08 cm²
Where the marks are
- Area of sector ≈ 52.33 cm² (½ mark)
- Area of equilateral triangle = 43.25 cm² (1 mark)
- Area of segment ≈ 9.08 cm² (½ mark)
Revise the chapter
- Chapter: Areas Related to Circles (notes, formulas, where marks are lost and every past question)
- Topic: Area of a Segment of a Circle
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.