Skip to content
MathsCBSE Class 10 · Basic · Board exam 2026, set 430/1/1 · 2 marks · Very short answer

CBSE Class 10 Mathematics Basic 2026: question 25

Set in the CBSE Class 10 board exam of 2026, paper 430/1/1, section B, question 25, for 2 marks. Try it first; the hints and our step-by-step solution are below.

Q25 · 2 marks · Very short answerAreas Related to Circles

A chord of a circle of diameter 20 cm subtends an angle of at the centre of the circle. Find the area of the corresponding minor segment of the circle. (Use and )

Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 430/1/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

Minor segment = sector − triangle formed by the two radii and the chord.

Hint 2

Radius is half the diameter. Use for the sector.

Hint 3

With a 60° angle between two equal radii, the triangle is equilateral, so its area is .

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. Radius cm, . Area of sector cm².

    ½ mark
  2. The two radii are equal and the included angle is , so the triangle is equilateral with side 10 cm. Area of triangle cm².

    1 mark
  3. Area of minor segment area of sector area of triangle cm² (approx.).

    ½ mark

Answer: Area of minor segment ≈ 9.08 cm²

Where the marks are

  • Area of sector ≈ 52.33 cm² (½ mark)
  • Area of equilateral triangle = 43.25 cm² (1 mark)
  • Area of segment ≈ 9.08 cm² (½ mark)

Revise the chapter

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.