CBSE Class 10 Mathematics Standard 2026: question 22(a)

Hints

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Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

1. Since $\angle B=90^{\circ }$, for angle A the opposite side is BC and the adjacent side is AB, so $\tan A=\frac{BC}{AB}$.

   $BC=\sqrt{(-8-1{)}^2+(7-1{)}^2}=\sqrt{81+36}=\sqrt{117}=3\sqrt{13}$

   ½ mark

2. $AB=\sqrt{(3-1{)}^2+(4-1{)}^2}=\sqrt{4+9}=\sqrt{13}$

   ½ mark

3. $\tan A=\frac{BC}{AB}=\frac{3\sqrt{13}}{\sqrt{13}}=3$

   1 mark

Answer: $\tan A=3$

Revise the chapter

• Chapter: Coordinate Geometry (notes, formulas, where marks are lost and every past question)
• Topic: Applications of the Distance Formula