CBSE Class 10 Mathematics Standard 2026: question 26(a)
Set in the CBSE Class 10 board exam of 2026, paper 30/4/1, section C, question 26(a), for 3 marks. Try it first; the hints and our step-by-step solution are below.
Q26(a) · 3 marks · Short answerCompetency-basedPair of Linear Equations in Two Variables
In a class test, Veer scored 6 more than twice as many marks as Kevin scored. If one of them had scored 4 more marks, their total score would have been 40. Find the marks obtained by Veer and Kevin.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 30/4/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Let the two scores be variables and translate each sentence into an equation.
Hint 2
Use and , then substitute.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
Let Veer's marks be and Kevin's marks be . Veer scored 6 more than twice Kevin's marks: ...(i)
- 1 mark
If one of them had scored 4 more, the total would be 40: , i.e. ...(ii)
- 1 mark
Substituting (i) in (ii): . Then . So Veer obtained 26 marks and Kevin obtained 10 marks.
Answer: Veer = 26 marks, Kevin = 10 marks
Where the marks are
- Forms (1 mark)
- Forms (1 mark)
- Solves to get and (½ + ½ marks)
Revise the chapter
- Chapter: Pair of Linear Equations in Two Variables (notes, formulas, where marks are lost and every past question)
- Topic: Word Problems on Linear Equations
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