The number of multiples of 4 lying between 12 and 250 is : (A) 59 (B) 59.5 (C) 60 (D) 61

MathsCBSE Class 10 · Standard · Board exam 2026, set 30/3/1 · 1 mark · MCQ

CBSE Class 10 Mathematics Standard 2026: question 6

Set in the CBSE Class 10 board exam of 2026, paper 30/3/1, section A, question 6, for 1 mark. Try it first; the hints and our step-by-step solution are below.

Q6 · 1 mark · MCQArithmetic Progressions

The number of multiples of 4 lying between 12 and 250 is :

(A)59
(B)59.5
(C)60
(D)61

Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 30/3/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

'Between' means 12 itself is not counted. Find the first and the last multiple of 4 in the range.

Hint 2

Use $a_{n} = a + (n - 1) d$ with $a = 16$ , $d = 4$ , $a_{n} = 248$ .

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

The multiples of 4 between 12 and 250 are $16, 20, \dots, 248$ . This is an AP with $a = 16$ and $d = 4$ .
$248 = 16 + (n - 1) 4 \Rightarrow n - 1 = 58 \Rightarrow n = 59$ . The answer is option (A).
1 mark

Answer: 59; option (A)

Where the marks are

Chooses option (A) 59 (1 mark)

Revise the chapter

Chapter: Arithmetic Progressions (notes, formulas, where marks are lost and every past question)

Practise this chapterBoard-style questions from Arithmetic Progressions, one at a time, marked against the answer key and marking points.Back to the full paper2026 board paper, set 30/3/1 (Standard): every question, by section.

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.

CBSE Class 10 Mathematics Standard 2026: question 6

Hints

Step-by-step solution

Revise the chapter

More questions from Arithmetic Progressions