CBSE Class 10 Mathematics Standard 2026: question 32(a)
Set in the CBSE Class 10 board exam of 2026, paper 30/3/1, section D, question 32(a), for 5 marks. Try it first; the hints and our step-by-step solution are below.
Q32(a) · 5 marks · Long answerStatistics
The median of the following data is 137. Find the values of x and y, given that total of frequencies is 68.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 30/3/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Make a cumulative frequency column in terms of x and y. The median 137 tells you which class is the median class.
Hint 2
Put l = 125, h = 20, f = 20, cf = 9 + x and n/2 = 34 into the median formula, then use the total 68 for y.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1½ marks
Cumulative frequency table:
Class f cf 65–85 4 4 85–105 5 9 105–125 x 9 + x 125–145 20 29 + x 145–165 14 43 + x 165–185 y 43 + x + y 185–205 4 47 + x + y - ½ mark
The median is 137, which lies in the class 125–145. So the median class is 125–145, with:
- 1 mark
Median :
- 1 mark
- 1 mark
Total frequency:
Answer: x = 13, y = 8
Where the marks are
- Correct cumulative frequency table (1½ marks)
- Identifies the median class 125–145 (½ mark)
- Substitutes correctly in the median formula (1 mark)
- Gets x = 13 (1 mark)
- Uses total 68 to get y = 8 (1 mark)
Revise the chapter
- Chapter: Statistics (notes, formulas, where marks are lost and every past question)
- Topic: Median of Grouped Data
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