CBSE Class 10 Mathematics Standard 2026: question 7
Set in the CBSE Class 10 board exam of 2026, paper 30/1/1, section A, question 7, for 1 mark. Try it first; the hints and our step-by-step solution are below.
Q7 · 1 mark · MCQTriangles
If ABC and DEF are similar such that AB = DE and BC = 8 cm, then EF is equal to :
- (A)4 cm
- (B)8 cm
- (C)12 cm
- (D)16 cm
Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 30/1/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Corresponding sides of similar triangles are in the same ratio.
Hint 2
Find AB/DE first.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
Since , .
- 1 mark
From we get . So , which gives cm. Option (d).
Answer: 16 cm, option (d)
Where the marks are
- Uses the ratio of corresponding sides to get EF = 16 cm, option (d) (1 mark)
Revise the chapter
- Chapter: Triangles (notes, formulas, where marks are lost and every past question)
More questions from Triangles
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- 2026 board paper, set 30/1/1 (Standard), Q22(B) · 2 marksIn the figure given above, Δ ABC ~ Δ XYZ, then find the values of x and y.
- 2026 board paper, set 30/1/1 (Standard), Q34(A) · 5 marksState and prove Basic Proportionality Theorem.
The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.