CBSE Class 10 Mathematics Standard 2026: question 29(A)
Set in the CBSE Class 10 board exam of 2026, paper 30/1/1, section C, question 29(A), for 3 marks. Try it first; the hints and our step-by-step solution are below.
Q29(A) · 3 marks · Short answerCircles
In the given figure, ABC is a right triangle in which B = , AB = 4 cm and BC = 3 cm. Find the radius of the circle inscribed in the triangle ABC.
Figure in the paper: Right triangle ABC with right angle at B (bottom right). A is at the top, C at bottom left, B at bottom right. A circle is inscribed inside the triangle touching all three sides. See it in the official paper.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 30/1/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
First find the hypotenuse AC.
Hint 2
Tangents drawn from a vertex to the incircle are equal. Let the tangent length from B be x.
Hint 3
Add the tangent lengths from A and C to get AC. Since ∠B = 90°, the tangent length from B equals the radius.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- ½ mark
In right , .
By Pythagoras theorem, cm.
- ½ mark
Let the incircle (centre O) touch AB at D, BC at E and CA at F. Let cm [tangents from an external point are equal].
- ½ mark
Then and [tangents from A and from C are equal].
- 1 mark
Since :
- ½ mark
In quadrilateral ODBE, , [tangent ⟂ radius] and . So ODBE is a square, and radius cm.
Hence the radius of the inscribed circle is 1 cm.
Answer: Radius = 1 cm
Where the marks are
- Finds AC = 5 cm (½ mark)
- Takes BD = BE = x using equal tangents (½ mark)
- Writes AD = AF = 4 − x and CE = CF = 3 − x (½ mark)
- Forms (4 − x) + (3 − x) = 5 and gets x = 1 (1 mark)
- Concludes radius = 1 cm, since ODBE is a square (½ mark)
- Alternative: equating area 6 cm² with ½·r·(4 + 3 + 5) to get r = 1 cm earns full marks
Revise the chapter
- Chapter: Circles (notes, formulas, where marks are lost and every past question)
More questions from Circles
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- 2026 board paper, set 30/2/1 (Standard), Q13 · 1 markIn the given figure, PA and PB are tangents to a circle centred at O. If ∠ OAB = 15°, then ∠ APB equals :
- 2026 board paper, set 30/2/1 (Standard), Q25 · 2 marksIn the given figure, O is the centre of the circle. PQ and PR are tangents. Show that the quadrilateral PQOR i…
The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.