The middle term of the A.P.: 10, 7, 4, …, -62 is: (A) -26 (B) -29 (C) -32 (D) -35

MathsCBSE Class 10 · Standard · Sample paper, session 2026-27 · 1 mark · MCQ

CBSE Class 10 Mathematics Standard sample paper 2026-27: question 5

From the official CBSE sample question paper for 2026-27, section A, question 5, for 1 mark. Try it first; the hints and our step-by-step solution are below.

Q5 · 1 mark · MCQArithmetic Progressions

The middle term of the A.P.: $10, 7, 4, \dots, - 62$ is:

(A) $- 26$
(B) $- 29$
(C) $- 32$
(D) $- 35$

Source: official sample paper from cbseacademic.nic.in (PDF). See it in the full Sample paper 2026-27.

Hints

Open one hint at a time and try again before the next.

Hint 1

First find how many terms there are.

Hint 2

With an odd number n of terms, the middle term is the $\frac{n + 1}{2}$ th term.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

Here $a = 10$ and $d = - 3$ . Use $a_{n} = a + (n - 1) d$ : $- 62 = 10 + (n - 1) (- 3)$ , so $n - 1 = 24$ and $n = 25$ .
With 25 terms, the middle term is the $\frac{25 + 1}{2} = 1 3^{t h}$ term: $a_{13} = 10 + 12 (- 3) = - 26$ . This is option (A).
1 mark

Answer: −26, option (A)

Where the marks are

Finds n = 25 and computes $a_{13} = - 26$ (1 mark)

Revise the chapter

Chapter: Arithmetic Progressions (notes, formulas, where marks are lost and every past question)
Topic: Finding nth Term from the Sum of n Terms

Practise this chapterBoard-style questions from Arithmetic Progressions, one at a time, marked against the answer key and marking points.Back to the full paperSample paper 2026-27 (Standard): every question, by section.

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CBSE Class 10 Mathematics Standard sample paper 2026-27: question 5

Hints

Step-by-step solution

Revise the chapter

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