CBSE Class 10 Mathematics Standard sample paper 2026-27: question 29
From the official CBSE sample question paper for 2026-27, section C, question 29, for 3 marks. Try it first; the hints and our step-by-step solution are below.
Q29 · 3 marks · Short answerCircles
Prove that the parallelogram circumscribing a circle is a rhombus.
Source: official sample paper from cbseacademic.nic.in (PDF). See it in the full Sample paper 2026-27.
Hints
Open one hint at a time and try again before the next.
Hint 1
Mark the four points of contact. From each vertex, two tangents are drawn to the circle; what do you know about their lengths?
Hint 2
Add the equal tangent lengths to get , then use the fact that opposite sides of a parallelogram are equal.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
Figure: ABCD is a parallelogram whose sides AB, BC, CD and DA touch a circle with centre O at S, P, Q and R respectively.
Tangents drawn from an external point to a circle are equal in length, so:
…(i)
…(ii)
…(iii)
…(iv)
- 1 mark
Adding (i), (ii), (iii) and (iv):
.
- 1 mark
In a parallelogram, opposite sides are equal, so and .
.
So the adjacent sides of parallelogram ABCD are equal, and all four sides are equal. Hence ABCD is a rhombus.
Answer: Proved: , so the parallelogram ABCD is a rhombus.
Where the marks are
- Writes the four pairs of equal tangent lengths with the reason (1 mark)
- Adds them to get (1 mark)
- Uses opposite sides of a parallelogram being equal to get and concludes it is a rhombus (1 mark)
Revise the chapter
- Chapter: Circles (notes, formulas, where marks are lost and every past question)
- Topic: Solving Problems Using Tangent Properties
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