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MathsCBSE Class 10 · Basic · Sample paper, session 2026-27 · 3 marks · Short answer

CBSE Class 10 Mathematics Basic sample paper 2026-27: question 30(A)

From the official CBSE sample question paper for 2026-27, section C, question 30(A), for 3 marks. Try it first; the hints and our step-by-step solution are below.

Q30(A) · 3 marks · Short answerStatistics

The mean of the following distribution is 48 and sum of all the frequencies is 50. Find the missing frequencies and .

Class20-3030-4040-5050-6060-70
Frequency8611

Source: official sample paper from cbseacademic.nic.in (PDF). See it in the full Sample paper 2026-27.

Hints

Open one hint at a time and try again before the next.

Hint 1

Use the total frequency 50 to get one equation in x and y.

Hint 2

Use the step-deviation mean formula with assumed mean 45 to get a second equation.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. Step-deviation table with , , :

    Class
    20-30825−2−16
    30-40635−1−6
    40-50x4500
    50-601155111
    60-70y6522y
    Total25 + x + y2y − 11
    1 mark
  2. ...(1)

    ½ mark
  3. Mean , so

    ½ mark
  4. ½ mark
  5. From (1),

    ½ mark

Answer: ,

Where the marks are

  • Correct table with total (1 mark)
  • Forms (½ mark)
  • Substitutes in the mean formula (½ mark)
  • y = 13 (½ mark)
  • x = 12 (½ mark)

Revise the chapter

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.