CBSE Class 10 Mathematics Standard 2025: question 23(a)
Set in the CBSE Class 10 board exam of 2025, paper 30/5/1, section B, question 23(a), for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q23(a) · 2 marks · Very short answerIntroduction to Trigonometry
It is given that . Use it to find the value of .
Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 30/5/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Write 15° as the difference of two standard angles.
Hint 2
Use A = 45° and B = 30°, then substitute their sine and cosine values.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- ½ mark
- 1 mark
- ½ mark
Answer:
Where the marks are
- Writes and applies the formula (½ mark)
- Substitutes the correct standard values (1 mark)
- Simplifies to (½ mark)
Revise the chapter
- Chapter: Introduction to Trigonometry (notes, formulas, where marks are lost and every past question)
- Topic: Relationships Between Trigonometric Ratios
More questions from Introduction to Trigonometry
- 2025 board paper, set 30/5/1 (Standard), Q30(b) · 3 marksLet 2A+B and A+2B be acute angles such that (2A+B) = (√(3))/(2) and (A+2B) = 1. Find the value of (4A-7B).
- 2024 board paper, set 30/3/1 (Standard), Q8 · 1 markIf θ = (√(3))/(2) and φ = 1/2, then (θ + φ) is:
- 2024 board paper, set 30/3/1 (Standard), Q25 · 2 marksEvaluate: 45°+ 60° 30°+ cosec 30°.
The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.