CBSE Class 10 Mathematics Standard 2025: question 21(b)

Hints

Open one hint at a time and try again before the next.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

1. Multiply the first equation by $\sqrt{3}$: $\sqrt{6}x+3y=5\sqrt{3}$ ...(1)

   ½ mark

2. Multiply the second equation by $\sqrt{2}$, using $\sqrt{8}\cdot \sqrt{2}=4$ and $\sqrt{6}\cdot \sqrt{2}=2\sqrt{3}$: $\sqrt{6}x-4y=-2\sqrt{3}$ ...(2)

   ½ mark

3. Subtract (2) from (1): $7y=7\sqrt{3}$, so $y=\sqrt{3}$.

   ½ mark

4. Substitute in the first equation: $\sqrt{2}x+3=5$, so $\sqrt{2}x=2$ and $x=\sqrt{2}$.

   ½ mark

Answer: $x=\sqrt{2}$, $y=\sqrt{3}$

Revise the chapter

• Chapter: Pair of Linear Equations in Two Variables (notes, formulas, where marks are lost and every past question)
• Topic: Graphical Method of Solving Linear Equations