CBSE Class 10 Mathematics Standard 2025: question 22(B)
Set in the CBSE Class 10 board exam of 2025, paper 30/4/1, section B, question 22(B), for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q22(B) · 2 marks · Very short answerTriangles
In parallelogram ABCD, side AD is produced to a point E and BE intersects CD at F. Prove that ABE CFB
Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 30/4/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Look for two pairs of equal angles between the triangles.
Hint 2
AD (and so AE) is parallel to BC; use alternate angles with transversal BE, and opposite angles of the parallelogram.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- ½ mark
Figure: parallelogram ABCD with AD produced beyond D to E; BE cuts CD at F.
- 1 mark
In and :
[opposite angles of a parallelogram]
[alternate angles, since and BE is a transversal] - ½ mark
Therefore [AA similarity criterion].
Answer: by AA similarity
Where the marks are
- Correct figure (½ mark)
- States the two pairs of equal angles with reasons (1 mark)
- Concludes similarity by AA (½ mark)
Revise the chapter
- Chapter: Triangles (notes, formulas, where marks are lost and every past question)
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.