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MathsCBSE Class 10 · Standard · Board exam 2025, set 30/4/1 · 2 marks · Very short answer

CBSE Class 10 Mathematics Standard 2025: question 22(B)

Set in the CBSE Class 10 board exam of 2025, paper 30/4/1, section B, question 22(B), for 2 marks. Try it first; the hints and our step-by-step solution are below.

Q22(B) · 2 marks · Very short answerTriangles

In parallelogram ABCD, side AD is produced to a point E and BE intersects CD at F. Prove that ABE CFB

Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 30/4/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

Look for two pairs of equal angles between the triangles.

Hint 2

AD (and so AE) is parallel to BC; use alternate angles with transversal BE, and opposite angles of the parallelogram.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. Figure: parallelogram ABCD with AD produced beyond D to E; BE cuts CD at F.

    ½ mark
  2. In and :
    [opposite angles of a parallelogram]
    [alternate angles, since and BE is a transversal]

    1 mark
  3. Therefore [AA similarity criterion].

    ½ mark

Answer: by AA similarity

Where the marks are

  • Correct figure (½ mark)
  • States the two pairs of equal angles with reasons (1 mark)
  • Concludes similarity by AA (½ mark)

Revise the chapter

  • Chapter: Triangles (notes, formulas, where marks are lost and every past question)

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.